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3 years ago

What (fog)(-3) is? Thank you for the help!

Mathematics

1 answer:

Verizon [17]3 years ago

5 0

F(g(x))=7g(x)+4

f(g(-3)=7 V(-3+4) + 4= 7*1+4=7+4=11

the answer is 11

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8 3/5 - 1 3/10 = ? this is fractions

Semenov [28]

1) $8 \frac{3}{5} - 1 \frac{3}{10}$

2) $8 \frac{6}{10} - 1 \frac{3}{10}$ =

3) $7\frac{3}{10}$

Answer
$7 \frac{3}{10}$

4 0

3 years ago

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Vanessa bought 6 feet of ribbon. She cut off 33 inches to wrap a package and 11 inches to decorate her scrapbook. How many inche

valentinak56 [21]

28 inches of the ribbon are left

3 0

3 years ago

What is 12/16 reduced?

levacccp [35]

3/4
You can divide both of them by 4. 12/4= 3 and 16/4= 4 Youre welcome

3 0

3 years ago

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Why is triangle MNL and KNL the same?

irinina [24]

They are the same because both triangles have the same every to the other triangle.

5 0

3 years ago

6. Steve is packing sacks for treats at a party. Every sack is exactly the same. Steve has 42 candy bars and 126 lollipops. a. W

Sergeu [11.5K]

Answer:

Greatest sack = 42

1 candy bar and 3 lollipops

Step-by-step explanation:

Represent Candy bars with C and Lollipops with L

$C = 42$

$L= 126$

Solving (a): Greatest number of treat sacks

To solve this, we simply calculate the GCF of C and L

$42 = 2^1 * 3^1 * 7^1$

$126 = 2^1 * 3^2 * 7^1$

Hence, the GCF is

$GCF = 2^1 * 3^1 * 7^1$

$GCF = 42$

Hence, greatest number of sack is 42

Solving (b): Number of treat in each sack.

To do this, we simply divide the number of C and L by the calculated GCF

For C:

$Treats = \frac{C}{GCF}$

$Treats = \frac{42}{42}$

$Treats = 1$

For L:

$Treats = \frac{L}{GCF}$

$Treats = \frac{126}{42}$

$Treats = 3$

Hence, 1 candy bar and 3 lollipops

8 0

3 years ago