All categories

3 years ago

Rational number between 5.2 and 5.5

Mathematics

2 answers:

Zinaida [17]3 years ago

8 0

5.3

or

5.4

or

5.48

Any of these is a rational number between 5.2 and 5.5.

GalinKa [24]3 years ago

8 0

Answer: 5.252525...

Step-by-step explanation: Since this decimal does not terminate, it could be an irrational number. However notice that the 25 after the decimal point repeats and remember that repeating decimals are rational numbers.

Therefore, 5.252525... is an example of a rational number.

You might be interested in

A jogger ran 5 2/3 mi on Tuesday. This was 2 1/4 more miles than she ran on Monday. How many miles did the jogger run on Monday?

Zepler [3.9K]

5 2/3-2 1/4=miles ran on Monday

5 8/12-2 3/12=miles ran on Monday

3 5/12=miles ran on Monday

7 0

3 years ago

PLZ help I am confusion. Math is hard

Andrej [43]

Answer:

It is C I am good at math

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can someone please answer question number 7 with explanation ❤️

Ulleksa [173]

Answer:

Step-by-step explanation:

you have to find the hole volume of the other shapes.

7 0

3 years ago

The quotient of a number x and -1.5 = 21

Lapatulllka [165]

Should be... x ÷ -1.5 = 21

4 0

3 years ago

Read 2 more answers

What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c

zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

4 0

2 years ago