Recurrence functions are used to preedict the subsequent value in a sequence. The fourth term of the sequence based on the recurrence relation is 25
<h3>How to find the recurrence relation of a function?</h3>
Given the recurrence relations according to the question
s(1) = 2 and
s(2)=3
s(k) =s(k-1)+2s(k-2)+6
If s(1) = 2, hence;
s(3) =s(3-1)+2s(3-2)+6
s(3) = s2 + 2s1 + 6
s(3) = 3 + 2(2) + 6
s(3) = 13
Determine the fourth term:
s(4) =s(4-1)+2s(4-2)+6
s(4) = s3 + 2s2 + 6
s(4) = 13 + 2(3) + 6
s(4) = 25
Hence the fourth term of the sequence based on the recurrence relation is 25
Learn more on recurrence relation here: brainly.com/question/10636530
The answer to 3 is C, because 18+15 is 33, and 33 divided into three equal groups would have 11 in each.
The answer to 4 is A, because in 11/3 3 can go into 11 3 times, with 2/3 remaining.
Answer:
here is the answer
Step-by-step explanation:
you may please search it
Answer:
imnuybtvcrxetyuiljhgfdsvbnjgfwertyunbvcserthfghjuytrewcnjuytredcnjuytggcggbggfbgggbgbgbgffgggbfbv v . ccxbgnnu
Step-by-step explanation:
