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grigory [225]
2 years ago
7

2.

Mathematics
1 answer:
Paraphin [41]2 years ago
5 0
<h3> Hope this attachment helps u</h3>

You might be interested in
andre has 4 times as many model cars as Peter , and Peter has one-third as many model cars as jade . andre has 36 model cars . a
lorasvet [3.4K]
P = how many cars Peter has
j = how many cars Jade has
a = how many cars Andre has
p x 4 = how many cars Andre has (36 model cars)
>>>TO FIND HOW MANY MODEL CARS PETER HAS:
p x 4 = 36
36 / 4 = 9
your equation to find how many model cars Peter has is:
36 / 4 = 9
So, Peter has 9 model cars.
>>>TO FIND HOW MANY MODEL CARS JADE HAS:
36 / 4 = how many cars Peter has (9)
Now, you are given the info that Jade has THREE TIMES (3x) as many cars as Peter already.
So, your equation for this one is:
9 x 3 = 27
So Jade has 27 model cars.

---- Jade has 27 model cars.
---- Andre has 36 model cars.
---- Peter has 9 model cars.

equation for a. 36 / 4 = p
equation for b. 9 x 3 = j
3 0
3 years ago
Read 2 more answers
Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit.
kherson [118]

Answer:

  • A.)  (3.6, 0.6)
  • D.)  (2.6, 0.4)

Step-by-step explanation:

See below for a graph.

___

Choices B, C, E can be eliminated on the basis that neither x nor g(x) can be negative. The domain of f(x) is x>0; the range of g(x) is x≥0.

7 0
2 years ago
Pls help me answer 2.2.3 and 2.2.4 <br>(2.2.4 needs to be converted)<br>ill give brainstorm​
Anarel [89]

\bold{\huge{\underline{ Solution }}}

<h3><u>Analysis </u><u>of </u><u>graph </u><u>:</u><u>-</u></h3>

We have given one graph which is plot between distance and time. where time is in minutes and distance is in seconds.

<u>According </u><u>to </u><u>the </u><u>graph </u>

  • For the first 5 minute ( O to A) , The distance is continously increasing 2m / per minute .
  • For the 5 minute that is from 5 minute to 13 minute ( A to B) both marellize and her dog wally moving with the constant speed .
  • For next 3 minutes that is from 10 minutes to 13 minutes ( B to C) , The distance is continously decreasing with time .
  • For next 3 minutes that is from 13 to 16 minutes ( C to D) , Again they moved with constant speed .
  • For next 6 minute that is from 16 to 21 minutes ( D to E) . Again, There distance is increasing with time .
  • Again For next 4 minutes that is 21 to 25 minutes , they are moving with constant velocity .

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

1) Between O and A

  • The marellize and wally when moving between O to A , The distance is constantly increasing with time.
  • The graph is Straight line

2) Between A and B

  • The marellize and wally when moving between A to B, The distance remains the same with time that is they moving with constant speed.
  • The graph is constant or steady

3) Between B to C

  • The marellize and wally when moving between B to C, The distance is constantly decreasing with time .
  • The graph is straight line but it follows decreasing function .

4) For covering the First 6 km ,

<u>According </u><u>to </u><u>the </u><u>graph</u><u>, </u>

  • For covering first 6 km, They took 3 minutes.

5) No, Marellize and wally walk does not from where they have started.

<u>According </u><u>to </u><u>the </u><u>graph </u>

  • It is end at 5 m instead of 0m .
3 0
2 years ago
I really need help please and thankyou
Jet001 [13]

Answer:

answer is (d) 4/3

Step-by-step explanation:

-x+3/7=2x-25/7

25/7+3/7=2x+x

28/7=3x

4=3x

x=4/3

7 0
3 years ago
Helppp me Please!!!!! :)
irina [24]

Answer:

x = 30 \\ y = 10

Step-by-step explanation:

8x + 6y = 300 \\ x + y = 40 \\ 6x + 6y = 240 \\ 2x = 60   \\ =  > x = 30 \\ y = 10

7 0
2 years ago
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