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grigory [225]
3 years ago
7

2.

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0
<h3> Hope this attachment helps u</h3>

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Pringles is planning their sales force spending for the next year. Each of their sales people spends about 3400 hours annually a
LUCKY_DIMON [66]

Answer:

459 sales people.

Step-by-step explanation

Time per call (t) = 45 min = 0.75 h

Hours per sales person (H) = 3,400 hours

Number of customers (n) = 40,000 customers

Call frequency (f)= 52 calls per year

The total number of sales people (S) needed, is given by the total time spent on calls for the year, divided by the amount of hours each person spends on sale:

S=\frac{40,000*0.75*52}{3,400}\\ S=458.8

Rounding up to the next whole person, Pringles needs 459 sales people.

3 0
3 years ago
Read 2 more answers
Helppppppp plssssssssss no unhelpful answer or I will delete
lara31 [8.8K]

Answer:

80 sq.in

Step-by-step explanation:

One square's side = 4in

One square's area = 16 sq. in

16 x 5 = 80 sq.in

Hope that helps!

3 0
2 years ago
Read 2 more answers
7.6.35 Question Help A pilot can travel 400 miles with the wind in the same amount of time as 352 miles against the wind. Find t
Law Incorporation [45]

9514 1404 393

Answer:

  21 miles per hour

Step-by-step explanation:

Let w represent the wind speed. Then the travel time is ...

  400/(329 +w) = 352/(329 -w)

  400(329 -w) = 352(329 +w)

  (352+400)w = 329(400 -352)

  w = (400 -352)/(400 +352)·329 = 48/752·329 = 21

The wind speed is 21 miles per hour.

5 0
2 years ago
How much would it cost to fence in this property if fencing costs $5.00 per foot?
stich3 [128]
The answer would be a 1425
5 0
3 years ago
For 0 ≤ θ &lt; 2 π what are the solutions to sin^2(θ) =2sin^2(θ/2)
gregori [183]

Recall the half-angle identity for sine,

sin²(x/2) = (1 - cos(x))/2

Then the given equation is identical to

sin²(θ) = 1 - cos(θ)

Also recall the Pythagorean identity,

sin²(θ) + cos²(θ) = 1

Then we rewrite the equation as

1 - cos²(θ) = 1 - cos(θ)

Factoring the left side, we have

(1 - cos(θ)) (1 + cos(θ)) = 1 - cos(θ)

and so

(1 - cos(θ)) (1 + cos(θ)) - (1 - cos(θ)) = 0

and we factor this further as

(1 - cos(θ)) (1 + cos(θ) - 1) = 0

which gives

cos(θ) (1 - cos(θ)) = 0

Then either

cos(θ) = 0   or   1 - cos(θ) = 0

cos(θ) = 0   or   cos(θ) = 1

[θ = arccos(0) + 2nπ   or   θ = -arccos(0) + 2nπ]

…   or   [θ = arccos(1) + 2nπ   or   θ = -arccos(1) + 2nπ]

(where n is any integer)

[θ = π/2 + 2nπ   or   θ = -π/2 + 2nπ]   or   [θ = 0 + 2nπ]

In the interval 0 ≤ θ < 2π, we get three solutions:

• first solution set with n = 0   ⇒   θ = π/2

• second solution set with n = 1   ⇒   θ = 3π/2

• third solution set with n = 0   ⇒   θ = 0

So, the first choice is correct.

6 0
3 years ago
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