To calculate the velocity, we use the given expression above which is <span>s(t) = −16t^2 + 144. First, we calculate the time it takes to reach the ground. Then, differentiate the expression and substitute time to the differentiated expression.
</span>s(t) = −16t^2 + 144
0 = -16t^2 + 144
t = 3
s'(t) = v = -32t
v = -32(3)
v = -96
Note: negative sign signifies that the object is going down
16.5 because it would 165 divided by 10, so if you were to round it’s 17 because you can’t really get half a person.
Step-by-step explanation:
<u>1</u><u> </u> x-y = 10
2
multiply by 2
2* (<u>1</u> x+y) =10
2
x+y=20
Well, the car depreciated in value by 12%, so you could say
x-12%, or just
x-0.12.
