Answer:
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is answer
plz mark as brainliest plz
Answer:
5:40
Step-by-step explanation:
This is a problem involving the least common difference.
If you know that the red and blue trains left at the same time at 5, you know that another red train will leave at 5:08. Another blue train at 5:10.
The way to solve this will be to write out the factors of 8 and 10 and find the smallest number that they overlap.
Red:
8, 16, 24, 32, 40, 48, 56, 64, 72, 80
Blue:
10, 20, 30, 40
You see that after 40 mnutes, they are both leaving the station again. After 40 minutes, at 5:40, they are both leaving.
She is incorrect cause if we take the number 20 and take 25% of it it equals 5 so now 20 is only 15. They if we take 75% away from 20 is equals 15 so then we only have 5 from 20 left. Therefore she’s incorrect because 75% leaves 5/20 and 25% leaves 15/20. Hope that makes sense.
The given sequence is
a₁, a₂, ...,

Because the given sequence is an arithmetic progression (AP), the equation satisfied is

where
d = the common difference.
The common difference may be determined as
d = a₂ - a₁
The common difference is the difference between successive terms, therefore
d = a₃ - a₂ = a₄ - a₃, and so on..
The sum of the first n terms is

Example:
For the arithmetic sequence
1,3,5, ...,
the common difference is d= 3 - 1 = 2.
The n-th term is

For example, the 10-term is
a₁₀ = 1 + (10-1)*2 = 19
Th sum of th first 10 terms is
S₁₀ = (10/2)*(1 + 19) = 100
13°, 66°, and 101° ......