Question

Write an equation in standard form of the line that contains the point (-1,2) amd is perpendicular to y = 3x - 1

Answer 1

Since it is perpendicular to y=3x-1, the slope must be a negative reciprocal.
there the slope of the perpendicular line is $-\frac{1}{3} x$

So now we have, 
$y=- \frac{1}{3} x+b$

To find b, we use the point that the line passes through and substitute it to the y and x values.

$2=- \frac{1}{3} (-1)+b$

which would give us b=5/3

Therefore, the equation of the line is 
$y=- \frac{1}{3} x+ \frac{5}{3}$