Answer:
8
Step-by-step explanation:
Lines have angles that are equal to 180. Therefore, because we already have 140 of the 180 necessary, we can subtract 140 from 180 to get 40. 40 divided by 5 is 8.
Hope that this helps!
Answer:
Step-by-step explanation:
let sum of zeros=s
and product of zeros=p
then quadratic equation is x²-sx+p=0
x²-(-1/2)x+(-3)=0
x²+1/2 x-3=0
2x²+x-6=0
A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)
The amount of sample that will remain after 4000 years is; 4.8357 mg
The number of years that it will take for only 17 mg of the sample to remain is; 1076 years
<h3>How to solve exponential decay function?</h3>
A) Using the model for radioactive decay;
m(t)= m₀e^(-rt)
where;
m₀ is initial mass
r is rate of growth
t is time
Thus, we are given;
m₀ = 27 mg
r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043
and so we have;
m(t) = 27e^(-0.00043t)
c) The amount that will remain after 4000 years is;
m(4000) = 27e^(-0.00043 * 4000)
m(4000) = 27 * 0.1791
m(4000) = 4.8357 mg
d) For 17 mg to remain;
17 = 27e^(-0.00043 * t)
17/27 = e^(-0.00043 * t)
In(17/27) = -0.00043 * t
-0.4626/-0.00043 = t
t = 1076 years
Read more about Exponential decay function at; brainly.com/question/27822382
#SPJ1
To find the incompleted portion of the test, convert the decimal to a percentage by moving the decimal two places to the right. .7 as a percentage is 70%. subtract 70% from 100%, giving you 30%. Juan has not completed 30% of his test, or 5 questions.
Answer:
a) 96% CI: 
b) If we estimate that the fraction of voters is 0.57, we can claim with 96% confidence that the error is equal or less than 0.06 from the estimated proportion.
Step-by-step explanation:
The proportion of the sample is
The standard deviation of the sample proportion is
For a 96% CI, the z-value is z=1.751.
Then, the 96% CI can be written as:
b) If we estimate that the fraction of voters is 0.57, we can claim with 96% confidence that the error is equal or less than 0.06 from the estimated proportion.
