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Nostrana [21]
3 years ago
10

Ratio of three angles of a triangle is 1 : 2 : 3. Find the angles.

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
8 0

Answer:

30⁰ , 60⁰ , 90⁰

Step-by-step explanation:

Let the angles x , 2x , 3x

By angle sum property:

x + 2x + 3x = 180⁰

6x = 180⁰

x = 30⁰

Angles are : 30⁰ , 60⁰ , 90⁰

Nikolay [14]3 years ago
4 0

Let one angle be x, the second 2x and the third 3x.

x + 2x + 3x = 180 degrees (angle sum property of a triangle)

6x = 180 degrees

x = 180/6

x = 30 degrees

So one angle is 30°, the second is 60°, and the third is 90°.

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Using elimination method
bogdanovich [222]

Answer:

The value of x is 2 and y is (-5)

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • -7x + y = – 19
  • -2x + 3y = – 19
<h3><u>To </u><u>Find</u>;</h3>
  • The value of x and y
<h3><u>B</u>y<u> </u><u>Usin</u>g<u> </u><u>Elimination</u><u> </u><u>Method</u>;</h3>

First name the equation

  • -7x + y = – 19 ...(1)
  • -2x + 3y = – 19 ...(2)

Now, Multiply equation (1) by 3 we get,

3 × (-7x + y = – 19)

-21x + 3y = – 57

Now, Eliminate

-21x + 3y = – 57

-2x + 3y = – 19

<u>+</u><u> </u><u> </u><u> </u><u> </u><u>–</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>+</u><u> </u><u> </u><u> </u><u> </u>

-19x = -38

x = -38/-19

x = 2

Now, Put the value of x in equation (2) we get the value of y.

-7x + y = – 19

-7(2) + y = – 19

-14 + y = -19

-14 + 14 + y = -19 + 14

y = -5

Thus, The value of x is (-5) and the value of y is 2.

<h3><u>For </u><u>Verification</u>;</h3>

-7x + y = – 19

-7(2) + (-5) = – 19

-14 – 5 = – 19

-19 = -19

-2x + 3y = – 19

-2(2) + 3(-5) = – 19

-4 – 15 = – 19

-19 = -19

Here, L.H.S = R.H.S

Hence Verified!

<u>-TheUnknownScientist 72</u>

4 0
2 years ago
Evaluate 4/49 × 7/13 give your answer as a fractions in its simplest form​
Anastasy [175]
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2 years ago
The radius of a right circular cylinder is given by √(t+6) and its height is 1/6√t , where t is time in seconds and the dimensio
denis23 [38]

Answer:

The rate change of volume of the cylinder is \frac{\pi}{4} ( \sqrt t+\frac2{ \sqrt t}) cubic inch per second.

Step-by-step explanation:

Given that the radius of right circular cylinder is \sqrt{(t+6)}  and its height is \frac16 \sqrt t where t is time in second and the dimension are inches.

\therefore r = \sqrt{(t+6)}

The base area of the cylinder is A= \pi r^2

                                                        =\pi (\sqrt{t+6})^2

                                                       = \pi (t+6)

\therefore A= \pi(t+6)

Differentiating with respect to t

\frac{dA}{dt}=\pi

\therefore h=\frac16\sqrt t

Differentiating with respect to t

\frac{dh}{dt}=\frac16 \times \frac12(t)^{\frac12-1}

\Rightarrow \frac{dh}{dt}=\frac1{12} (t)^{-\frac12}

The volume of cylinder is V= Ah

∴V= Ah

Differentiating with respect to t

\frac{dV}{dt}=A\frac{dh}{dt}+h\frac{dA}{dt}

    =\pi (t+6). \frac1{12}t^{-\frac12} +\frac16\sqrt t . \pi

   =\pi. \frac1{12}.t^{\frac12}+\pi . 6.\frac1{12} t^{-\frac12} +\pi\frac16 \sqrt t

   =\frac{\pi}{4} ( \sqrt t+\frac2{ \sqrt t})

The rate change of volume of the cylinder is \frac{\pi}{4} ( \sqrt t+\frac2{ \sqrt t}) cubic inch per second.

5 0
3 years ago
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