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3 years ago

Can someone help me ? I need to get the answer but I don’t know how to do it?

Mathematics

2 answers:

alexgriva [62]3 years ago

7 0

Answer:

D) 29.41 oz

Step-by-step explanation:

Maya has 15 cousins, which means she is making 15 bags.

She has 441.15 oz of candy in all. Divide 441.15 with 15:

441.15/15 = 29.41

29.41 oz is your answer, or D).

Elena-2011 [213]3 years ago

7 0

Answer:

Step-by-step explanation:

441.15/ 15

I calculated it.

Have a nice day!

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What the 15th sequence for 4.5n-8

damaskus [11]

Given:
The sequence formula;
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Required:
15th term = ?

Procedure:
All you need to do is use n = 15

T15 = 4.5(15) - 8
T15 = 59.5

Conclusion:
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3 years ago

How do you write 0.4335 as a fraction

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Alex is making puppets for a show. He bought all the string needed for $125. It costs $18 for the remaining materials to make ea

Alexus [3.1K]

Alex bought all the string needed for $125.

It costs $18 for the remaining materials to make each puppet.

So if we closely observe then we see that here $125 is the fixed cost because its not going to change with number of puppets.

And the variable cost is $18.

In this case we can model a Total cost function C(x) for for x number of puppets as below

$C(x)=125+18x\\ \\ \text{Here x is the number of puppets}\\ \\ \text{Since in our case the number of puppets is 50 so replace x by 50 we get }\\ \\ C(50)=125+18*50\\ \\ C(50)=125+900\\ \\ C(50)=1025 \ dollar.$

The total cost to make 50 puppets=$1025

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3 years ago

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12 out of 15 students play in the school band. In a class of 45 students, how many do NOT play in the band? HELP!

Elza [17]

Answer:

9 students

Step-by-step explanation:

because 15x 3 = 45 so 12x3= 36 so 45-36= 9 Can i be branliest

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3 years ago

If cos(θ)=2853 with θin Q IV, what is sin(θ)?

marysya [2.9K]

Answer: $\sin \theta=\frac{-45}{53}$

Step-by-step explanation:

Since we have given that

$\cos\theta=\frac{28}{53}$

And we know that θ is in the Fourth Quadrant.

So, Except cosθ and sec θ, all trigonometric ratios will be negative.

As we know the "Trigonometric Identity":

$\cos^2\theta+\sin^2\theta=1\\\\\sin \theta=\sqrt{1-\cos^2\theta}\\\\\sin \theta=\sqrt{1-(\frac{28}{53})^2}=\sqrt{\frac{53^2-28^2}{53^2}}\\\\\sin \theta=\sqrt{\frac{2025}{53^2}}\\\\\sin \theta=\frac{45}{53}$

It must be negative due to its presence in Fourth quadrant.

Hence, $\sin \theta=\frac{-45}{53}$

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3 years ago