Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
Answer:
86 cm²
Step-by-step explanation:
Ok, so since 4 circles fit in the square, each circle's diameter must be 10.
Which means the radius of each circle is 5 because 10 ÷ 2 = 5.
Now we can solve for area.
A = πr²
A = 3.14 x 5²
A = 3.14 x 25
A = 78.5 cm²
78.5 cm² is the area of one circle so we multiply that by 4.
78.5 x 4 = 314 cm²
Now we subtract from the area of the square.
20 x 20 = 400 cm²
400 - 314 = 86 cm²
Answer:
47.5%
Step-by-step explanation:
You have to first subtract 80 and 42 to find the decrease first. This is 38. Now, you have to divide this by the original number which is 80. So 38 divided by 80 is 0.475.
Now multiply this by 100.
You can easily move the decimal point to the right.
So you would get 47.5%
Hope this helped!
