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mart [117]
3 years ago
9

Maggie is considering two investments. Investment A Investment B Principal $10,000 $8,000 Interest rate 3% 2.8% Time in years 5

15 Which investment will be worth more at the end of the investment period?
Mathematics
2 answers:
OverLord2011 [107]3 years ago
8 0

Answer:

investment A will be worth than investment B at the end of the investment period.

Step-by-step explanation:

lana [24]3 years ago
3 0
To solve this we are going to use the simple interest formula: A=P(a+rt)
where
A is the final amount.
P is the initial investment. 
r is the interest rate in decimal form.
t is the time in years. 

Investment A. We know that the initial investment is $10,000, so P=10000. We also know that the number of years is 5, so t=5. To convert the interest rate to decimal form, we are going to divide the rate by 100%
r= \frac{3}{100} =0.03
Lets replace those values in our formula to find A:
A=P(a+rt)
A=10000(1+0.03*5)
A=11500

Investment B. P=8000, t=15, and r= \frac{2.8}{100} =0.028.
A=P(a+rt)
A=8000(1+0.028*15)
A=11360

We can conclude that investment A will be worth than investment B at the end of the investment period.
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Answer:

1. The volumes are equal.

2. The base areas are equal.

3. The prisms have the same height.

Step-by-step explanation:

I don't see no answered to check all that apply but here is the answers about properties and two prisms

7 0
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7 0
3 years ago
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Please answer this correctly
Nana76 [90]

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20 / 100 = x / 55

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8 0
3 years ago
A number b increased by 8 is greater than 18
Fed [463]

Answer: b > 10

Step-by-step explanation:

b + 8 > 18

Subtract 8 from both sides

that leaves you with

b > 10

5 0
3 years ago
Ionizing radiation is being given increasing attention as a method for preserving horticultural products. A study reports that 1
kolbaska11 [484]

Answer:

Yes, there is  enough evidence to support the claim that ionizing radiation is beneficial in terms of marketability.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that ionizing radiation is beneficial in terms of marketability.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

Being π1: the true proportion of treated bulbs that can be comercialized after 240 days, and π2: the true proportion of untreated bulbs that can be comercialized after 240 days.

The significance level is 0.05.

The sample 1, of size n1=180 has a proportion of p1=0.85.

p_1=X_1/n_1=153/180=0.85

The sample 2, of size n2=180 has a proportion of p2=0.65.

p_2=X_2/n_2=117/180=0.65

The difference between proportions is (p1-p2)=0.2.

p_d=p_1-p_2=0.85-0.65=0.2

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{153+117}{180+180}=\dfrac{270}{360}=0.75

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.75*0.25}{180}+\dfrac{0.75*0.25}{180}}\\\\\\s_{M_d}=\sqrt{0.001+0.001}=\sqrt{0.002}=0.0456

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.2-0}{0.0456}=\dfrac{0.2}{0.0456}=4.382

This test is a right-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t>4.382)=0.000008

As the P-value (0.000008) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that ionizing radiation is beneficial in terms of marketability.

7 0
3 years ago
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