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statuscvo [17]
2 years ago
7

Find a formula for a_n (for the geometric sequence), then find the 8th term. Solve for both or one of these questions, thank you

so much!

Mathematics
1 answer:
kati45 [8]2 years ago
4 0

Answer:

2a. aₙ = 12 * -2ⁿ⁻¹; a₈ = -1536

2b. aₙ = 4 * 3ⁿ⁻¹; a₈ = 8748

Step-by-step explanation:

The geometric sequence formula is aₙ = a₁ * rⁿ⁻¹.

2a:

a₈ = 12 * -2⁸⁻¹ <em>{Subtract 1 from 8 to get 7}</em>

a₈ = 12 * -2⁷ <em>{2⁷ is 128. Since the exponent is odd, this will be negative.}</em>

a₈ = 12 * (-128) <em>{Multiply 12 by -128 to get -1536.</em>

a₈ = -1536

2b:

a₈ = 4 * 3⁸⁻¹ <em>{Subtract 1 from 8 to get 7)</em>

a₈ = 4 * 3⁷ <em>{7 is the 3rd number after 4 (a multiple of 4). As a result, this will end in a 7. 3⁷ is 218</em><em>7</em><em>.}</em>

a₈ = 4 * 2187 <em>{Multiply 4 by 2187 to get 8748}</em>

a₈ = 8748

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Full Question

Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordless, and the other six are corded phones. Suppose that these components are randomly allocated the numbers 1, 2, . . . , 18 to establish the order in which they will be serviced.

What is the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced?

What is the probability that two phones of each type are among the first six serviced?

Answer:

a. 0.149

b. 0.182

Step-by-step explanation:

Given

Number of telephone= 18

Number of cellular= 6

Number of cordless = 6

Number of corded = 6

a.

There are 18C6 ways of choosing 6 phones

18C6 = 18564

From the Question, there are 3 types of telephone (cordless, Corded and cellular)

There are 3C2 ways of choosing 2 out of 3 types of television

3C2 = 3

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12C6 = 924

There are 2 * 6C6 * 6C0 ways of choosing none from any of these two types of phones

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= 0.149

b)

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= (6C2)³

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= 0.182

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