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3 years ago

Does anyone know what to do. It’s for 6th grade math. The pencil part is a guess that I did.

Mathematics

1 answer:

HACTEHA [7]3 years ago

5 0

Hullo! this looks complicated i know, but it's actually quite simple. if 2 bars feed 6 aliens, that means every number on top will be one third of the number on the bottom. so it would go like this (I'll go up to 9, and it should make sense from there)

2 | 2.3 | 2.6 | 3
------------------------
6 | 7 | 8 | 9

i hope this helped! if all else fails, just ask for help. it really does go a long way

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How tall would the tree be?

Ksivusya [100]

Answer:

26 feet

Step-by-step explanation

3 0

3 years ago

Find equivalent ways to rewrite the expression 6a^8÷3a^4

solong [7]

Answer:

6a^8/3a^4= (6/3)= 2

a^8/a^4= a^4

2a^4

(6/3)(a^8/a^4)= 2a^4

(6/3)(a^(8-4))= 2a^4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is 4/5 times 7/12

slamgirl [31]

Answer:

$\frac{28}{60}$ ( $\frac{7}{15}$ )

Step-by-step explanation:

b/c 4/5*7/12

means 4*7 and 5*12

then28/60

hope it's helpful

THANK YOU.

3 0

3 years ago

Which of the following combined with the equation −9x + 3y = 12 creates a system of linear equations with no solution?

Mumz [18]

Answer:

Step-by-step explanation:

You can't get an exact answer to this because there are no choices.

Add 9x to both sides.

3y = 9x + 12 Divide by 3

3y/3 = 9x/3 + 12/3 Combine

y = 3x + 4

Now to get anything at all that is parallel to this and providing no answer because there is no intersection of the two lines, just change the 4 to something else. Here's one example

y = 3x + 8

As long as the number in front of the x's is the same, they are parallel with no point in common.

8 0

3 years ago

A box has a volume of 308 cm cubed. Its height is 4 cm greater than its length. Its length is 3 cm greater than its width. What

kifflom [539]

Answer:

4 cm.

Step-by-step explanation:

Given:

A box has a volume of 308 cm cubed.

Its height is 4 cm greater than its length.

Its length is 3 cm greater than its width.

Question asked:

What is the width of the box?

Solution:

Let width = $x\ cm$

Length = $x+3\ cm$

Height = $x+3+4=x+7\ cm$

As we know:

$Volume\ of\ box=length\times width\times height$

$308=(x+3)\times x\times(x+7)\\ \\ 308=(x^{2} +3x)(x+7)\\ \\ 308=x^{2} (x+7)+ 3x(x+7)\\ \\ 308=x^{3} +7x^{2} +3x^{2} +21x\\ \\ 308=x^{3} +10x^{2} +21x\\ \\ Subtract\ 308\ from\ both\ sides\\ \\ x^{3} +10x^{2} +21x-308=0\\ \\ factor\ left\ side\ of\ equation\\ \\ (x-4)(x^{2} +14x+77)=0\\ \\ Set\ factors\ equal\ to\ 0.\\ \\ x-4=0 \ or\ x^{2} +14x+77=0\\ \\ \\$

As width can never be in negative, $x= 4\ cm$

By substituting the value:-

Width = $x\ cm$ = 4 cm

Thus, width of the box is 4 cm.

4 0

3 years ago