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3 years ago

Does anyone know what to do. It’s for 6th grade math. The pencil part is a guess that I did.

Mathematics

1 answer:

HACTEHA [7]3 years ago

5 0

Hullo! this looks complicated i know, but it's actually quite simple. if 2 bars feed 6 aliens, that means every number on top will be one third of the number on the bottom. so it would go like this (I'll go up to 9, and it should make sense from there)

2 | 2.3 | 2.6 | 3
------------------------
6 | 7 | 8 | 9

i hope this helped! if all else fails, just ask for help. it really does go a long way

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QUICK HELP

mart [117]

Answer:

the common ratio is

1/3

because

9*1/3=3

3*1/3=1

1*1/3=1/3

...

8 0

3 years ago

Can someone help me pls

VLD [36.1K]

Answer:

-12

Step-by-step explanation:

Since a = -6,we have to multiply 2 and -6,and you get -12 bc we have to put the sign of the bigger digit which is -6 in this problem,so you have to write -12

4 0

2 years ago

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

5 0

3 years ago

The weights of a large number of miniature poodles are approximately normally distributed with a mean of 8 kilograms and a stand

harina [27]

Answer and Step-by-step explanation:

Considering the table attached.

(a) over 9.5 kg;

μ = 8

σ = 0.9

z = 9.5 - 8/0.9 ≈ 1.67

P (Z > 1.67) = 0.5 - P(0<Z<1.67) = 0.5 - 0.4525 = 0.0475

(b) at most 8.6 kg;

z = 8.6-8/0.9 ≈ 0.67

P(Z < 0.67) = 0.5 + P(0<Z<0.67) = 0.5 + 0.2486 = 0.7486

z₁ = 7.3-8/0.9 ≈ -0.78

z₂ = 9.1 - 8/0.9 ≈ 1.22

P(-0.78 < Z < 1.22) = P(0 < Z < 0.78) + P(0 < Z < 1.22) = 0.2823 + 0.3888 = 0.6711

3 0

3 years ago

HELP I NEED ANSWERS FAST ITS E.L.A

Pavel [41]

“huh” is the interjection!

5 0

3 years ago

Read 2 more answers