Make "a" the subject of:

Mathematics

1 answer:

slamgirl [31]3 years ago

7 0

Answer:

a=m-x^2/k^2

Step-by-step explanation:

(k^2(m-a)) /x=x

K^2(m-a)=x^2

m-a=x^2/k^2

a=m-x^2/k^2

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Evaluate the expression when p= -24 and q = 4.

Talja [164]

$(2 \times - 24) \div - 4$
which comes out as 12

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3 years ago

Please help it is math

olasank [31]

Answer:

A linear function has the form y=mx+b

A line has a proportional relationship if y/x is always the same ratio for any value.

The slope m=(y2-y1)/(x2-x1) for some two points on a line is always constant, else it wouldn't create a line.

A line won't be proportional if you adapt b because the ratio of y/x won't match the slope anymore.

In the end this means all lines with proportional relationships must intersect (0,0) or in other words f(0)=0.

This happens if they have the shape y=mx.

Step-by-step explanation:

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3 years ago

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aleksklad [387]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

The equation line l is given by the equation y= 7/4x+3. line m goes through the point ( –1,4) and is perpendicular to line l whi

mr_godi [17]

We determine line m as follows:

*First, by theorem we have the following:

$m_1=-\frac{1}{m_2}$

Here m1 & m2 are the slopes of two perpendicular lines. For all lines that are perpendicular that is true, so we calculate the slope of line m using the slope of the function given [Which has a slope of 7/4]:

$m_1=-\frac{1}{\frac{7}{4}}\Rightarrow m_1=-\frac{4}{7}$

So, the slope of line m is -4/7. Now, using this slope and the point (-1, 4) we replace in the following expression:

$y-y_1=m_1(x-x_1)$

Here x1, y1 & m1 are the x-component of the point, the y-component of the point, and the slope of the line respectively, so we replace and solve for y: