When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.
When we are attempting limits questions, there are several tests we attempt first.
1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
![\lim_{x \to 0} (\frac{sinx}{x}) = 1](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%7D%20%28%5Cfrac%7Bsinx%7D%7Bx%7D%29%20%3D%201)
![\lim_{x \to 0} (\frac{tanx}{x}) = 1](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%7D%20%28%5Cfrac%7Btanx%7D%7Bx%7D%29%20%3D%201)
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.
For example:
1)
![\lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%7D%5Cfrac%7B%5Csqrt%7Bx%7D%20-%205%7D%7Bx%20-%2025%7D)
We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>Substitute x = 0 to the function.
![\frac{\sqrt{0} - 5}{0 - 25}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B0%7D%20-%205%7D%7B0%20-%2025%7D)
![= \frac{-5}{-25}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B-5%7D%7B-25%7D)
<em>Method 2: Rearranging the function
</em>We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.
![\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%7D%5Cfrac%7B%28%5Csqrt%7Bx%7D%20-%205%29%7D%7B%28%5Csqrt%7Bx%7D%20-%205%29%28%5Csqrt%7Bx%7D%20%2B%205%29%7D)
![= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}](https://tex.z-dn.net/?f=%3D%20%5Clim_%7Bx%20%5Cto%200%7D%5Cfrac%7B1%7D%7B%28%5Csqrt%7Bx%7D%20%2B%205%29%7D%7D)
![= \frac{1}{5}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B5%7D)
Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 can go into 17 twice with one left over so
the answer is 2 1/8
Hope this helps!!!
Answer:
6 and 48
Step-by-step explanation:
when t=1, the expression is 6
when t=4, the expression is 48
:)
Only 1,4 2,3 3,2 4,1
there are 6x6 =36 combination
so 4/36 =1/9
the answer is 1/9
Answer:
1. is no
Step-by-step explanation:
.