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2 years ago

Simplify the expression: 1+24432+21d+31d

Mathematics

2 answers:

Elenna [48]2 years ago

7 0

Answer:

52d+24433 is the correct answer

Alex787 [66]2 years ago

5 0

Answer:

24433+52d

Step-by-step explanation:

Simplify by adding

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10 points someone help me please!?

Soloha48 [4]

Answer:

$\large\boxed{b=\sqrt{95}}$

Step-by-step explanation:

Use the Pyhagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=b,\ leg=7,\ hypotenuse=12$

Substitute:

$b^2+7^2=12^2$

$b^2+49=144$ <em>subtract 49 from both sides</em>

$b^2=95\to b=\sqrt{95}$

7 0

3 years ago

Pls show work thank you!!!

Nastasia [14]

$|-16-x|=0\\\\\implies -16-x = 0\\\\\implies x = -16$

8 0

2 years ago

In a video game, the chance of rain each day is always 30%. At the beginning of each day in the video game, the computer generat

Scorpion4ik [409]

Answer:

I would divide 50 by 4 (Because there are usually 4 weather conditions in game) and whichever the number is closest to it would pick that weather condition

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2 years ago

Question 1

grandymaker [24]

Answer:

see attached

angles: 39.8°, 68.2°; side: 8

Step-by-step explanation:

The triangle and its measurements are shown in the attachment.

_____

If you do this with pencil and paper and protractor, likely your angle measurements will only be to the nearest degree.

8 0

3 years ago

Tomika heard that the diagonals of a rhombus are perpendicular to each other. Help her test her conjecture. Graph quadrilateral

Stella [2.4K]

Answer:

a. The four sides of the quadrilateral ABCD are equal, therefore, ABCD is a rhombus

b. The equation of the diagonal line AC is y = 5 - x

The equation of the diagonal line BD is y = 5 - x

c. The diagonal lines AC and BD of the quadrilateral ABCD are perpendicular to each other

Step-by-step explanation:

The vertices of the given quadrilateral are;

A(1, 4), B(6, 6), C(4, 1) and D(-1, -1)

a. The length, l, of the sides of the given quadrilateral are given as follows;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

The length of side AB, with A = (1, 4) and B = (6, 6) gives;

$l_{AB} = \sqrt{\left (6-4 \right )^{2}+\left (6-1 \right )^{2}} = \sqrt{29}$

The length of side BC, with B = (6, 6) and C = (4, 1) gives;

$l_{BC} = \sqrt{\left (1-6 \right )^{2}+\left (4-6 \right )^{2}} = \sqrt{29}$

The length of side CD, with C = (4, 1) and D = (-1, -1) gives;

$l_{CD} = \sqrt{\left (-1-1 \right )^{2}+\left (-1-4 \right )^{2}} = \sqrt{29}$

The length of side DA, with D = (-1, -1) and A = (1,4) gives;

$l_{DA} = \sqrt{\left (4-(-1) \right )^{2}+\left (1-(-1) \right )^{2}} = \sqrt{29}$

Therefore, each of the lengths of the sides of the quadrilateral ABCD are equal to √(29), and the quadrilateral ABCD is a rhombus

b. The diagonals are AC and BD

The slope, m, of AC is given by the formula for the slope of a straight line as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Therefore;

$Slope, \, m_{AC} =\dfrac{1-4}{4-1} = -1$

The equation of the diagonal AC in point and slope form is given as follows;

y - 4 = -1×(x - 1)

y = -x + 1 + 4

The equation of the diagonal AC is y = 5 - x

$Slope, \, m_{BD} =\dfrac{-1-6}{-1-6} = 1$

The equation of the diagonal BD in point and slope form is given as follows;

y - 6 = 1×(x - 6)

y = x - 6 + 6 = x

The equation of the diagonal BD is y = x

c. Comparing the lines AC and BD with equations, y = 5 - x and y = x, which are straight line equations of the form y = m·x + c, where m = the slope and c = the x intercept, we have;

The slope m for the diagonal AC = -1 and the slope m for the diagonal BD = 1, therefore, the slopes are opposite signs

The point of intersection of the two diagonals is given as follows;

5 - x = x

∴ x = 5/2 = 2.5

y = x = 2.5

The lines intersect at (2.5, 2.5), given that the slopes, m₁ = -1 and m₂ = 1 of the diagonals lines satisfy the condition for perpendicular lines m₁ = -1/m₂, therefore, the diagonals are perpendicular.

5 0

3 years ago