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3 years ago

Please give me the answer to number 5 and explain how to do it.

Mathematics

1 answer:

Goryan [66]3 years ago

4 0

The equation is simply 8s where s is the length of a side. There are 8 sides. You are just adding the length of all 8 sides together to get the perimeter.

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Pleas help me if this is correct

Vesna [10]

Answer:

yes, i think it is

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

M^2-10m+9=(m-9)( ) filling the missing factor to complete the equation

Romashka [77]

Answer:

m-1

Step-by-step explanation:

3 0

3 years ago

The baseball coach is 70 inches tall. How tall is the child?

tankabanditka [31]

The child is <u>59.4 inches tall</u>, assuming the length from the coach's shoulder to his head cap is approximately 10 inches.

<h3>What is Heigth?</h3>

Height refers to the vertical distance between the top and bottom of something.

Height measures the length of some objects or persons vertically to determine whether it is high or low, according to some ascertained criteria.

<h3>Data and Calculations:</h3>

Baseball coach's height = 70 inches

Coach's shoulder to head = 10.6 inches

Height of the child standing slightly below the coach's shoulder = 59.4 inches (70 - 10.6)

Thus, the child standing slightly below the coach's shoulder is 59.4 inches tall.

Learn more about height measurements at brainly.com/question/73194

#SPJ1

<h3>Question Completion:</h3>

Assume that the height of the coach from his shoulder to the head is 10.6 inches.

6 0

2 years ago

Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

3 years ago

Anybody know what the answer is

koban [17]

5. million 6. Ten thousand

6 0

3 years ago