Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.
Answer:
24 ft
Step-by-step explanation:
Use proportions! The old tent has sides of 10ft, and a base of 15ft. The new tent has sides of 16ft and a base of ____ ft.
So, 10/15 = 16/___. Cross multiple and you get 24ft!
Answer:
everyone gets 5 pieces and the rest gets thrown out
Step-by-step explanation:
29/5=5.8
but obviously ur not gonna break the candy into .8 so everyone just gets 5 so its even
Answer:
2) 11
3) 21
4) 7
Step-by-step explanation:
2) (-6) -(-17) = 17 - 6 = 11
3) 19 - (-2) = 19 + 2 = 21
4) (-13) + 20 = 20 - 13 = 7
Answer:
531.167 ft²
Step-by-step explanation:
Given data
Dimension of pool
Diameter =24ft
Radius =12ft
If the cover must hang by 1ft around, then the diameter is 26ft
Radius =13ft
Area of cover = πr²
Substitute
Area = 3.142*13²
Area =3.143*169
Area =531.167 ft²
Hence the minimum area is 531.167 ft²
