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3 years ago

Do you need to execute the Distributive Property to simplify: 5(2-8)? Yes No

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

7 0

It’s no for your question

Ahat [919]3 years ago

6 0

no just do the stuff in the parentheses then multiply by 5

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A Shop sells two different bags of rice .

DIA [1.3K]

Answer:

b gives you more free rice

Step-by-step explanation:

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3 years ago

I don’t know how to do this

Rina8888 [55]

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3 years ago

What is the length of the line?

lesya692 [45]

could you further explain?

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3 years ago

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The formula for finding the length of an arc on a circle is L=2πr(x360) , where r is the radius of the circle and x is the measu

horrorfan [7]

The formula for length of an arc on a circle is given by the formula:

$L = \frac{2 \pi rx}{360}$ ,

where 'r' is the radius of the circle and 'x' is the measure of the central angle of the arc.

We have to determine the value of radius 'r'.

Since, $L = \frac{2 \pi rx}{360}$

By Cross multiplication, we get

$360 \times L = 2 \pi rx$

$\frac{360 \times L}{ 2 \pi x} =r$

$\frac{180 \times L}{ \pi x} =r$

$r = \frac{180L}{ \pi x}$

Therefore, the radius 'r' is given by $r = \frac{180L}{ \pi x}$ .

Option 4 is the correct answer.

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3 years ago

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How do find the domain and range of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx-8%7D%7D" id="TexFormula1" tit

Kisachek [45]

$\sqrt{x-8}$ is undefined if the argument $x-8$ is negative, so you first need to require that

$x-8\ge0\implies x\ge8$

We're not done yet, though, because $\dfrac1{\sqrt{x-8}}$ still doesn't exist when $x=8$ , so we remove this from the domain and we're left with $x>8$ , or in interval notation, $(8,\infty)$

To find the range, consider the limits of the function as you approach either endpoint of the domain.

$\displaystyle\lim_{x\to8^+}\frac1{\sqrt{x-8}}=+\infty$
$\displaystyle\lim_{x\to\infty}\frac1{\sqrt{x-8}}=0$

Since $\dfrac1{\sqrt{x-8}}$ is positive everywhere, the range is $(0,\infty)$

3 0

3 years ago