Answer:
117
Step-by-step explanation:
Hello!
First you have to count how many tallies the car went 9 tallies
Multiply the amount of tallies by how far they represent
9 * 0.8 = 7.2 meters
The car when 7.2 meters in half a second so we double this to get how fast it was going a second
7.2 * 2 = 14.4
The answer is 14.4 m/s
Hope this helps!
Answer:
Step-by-step explanation:
To find the length and width of the figure given the equation (s-2) (s+6) = 153, we will find the equivalent value of s by factoring.
(s-2) (s+6) = 153
s²+6s-2s-12 = 153
s²+4s-12-153 = 0
s²+4s-165 = 0
s²+15s-11s-165 = 0
s(s+15)-11(s+15) = 0
s+15(s-11) = 0
s+15 = 0 and s-11 = 0
s = -15 and 11
s cannot be negative
Hence s = 11
The length of the figure is s
The width is s+6
Length = 11
Width = 11+6 = 17
Hence the length of the figure is 11 and the width is 17
(b+8) * 5b^2
__________
b * (b^2-64)
(b+8)*5*b^2
__________
b*(b-8)*(b+8)
5b
___
(b-8)
Check, say b = 1: my result is 5/(-7), the original: 9/1:-63/5 = -45/63=-5/7! Yup!