All categories

3 years ago

A model deck is 9 in. By 16 in. Use the scale 1/2 in. : 1 ft to find the dimensions s of the actual deck.

Mathematics

2 answers:

Rainbow [258]3 years ago

5 0

S=9in(1ft/0.5in) by 16in(1ft/0.5in)

s=18ft by 32ft

xxTIMURxx [149]3 years ago

4 0

If the scale says 1/2 inch is equal to a foot then you can divide 9 by 1/2 to get 18. The units would then change to feet so this is one portion of the real dimensions of the deck. You would then do the same for 16 inches and the other dimension would be 32 feet.

The dimensions for the real deck are 18 feet by 32 feet.

I hope this helps you :D

You might be interested in

Solve for m 11m − 10m = 14

BaLLatris [955]

M would be 14 because:
11x14-10x14=14

7 0

3 years ago

I’m stuck help quick please

aev [14]

Answer:

C) AB/XY = AC/XZ

Step-by-step explanation:

ΔXYZ is a dialation of ΔABC by a scale factor of 5, so ΔXYZ ≅ ΔABC

AB/XY = AC/XZ = BC = YZ

So answer is C. AB/XY = AC/XZ

4 0

3 years ago

Graph the solution...please helppp me

Olenka [21]

The slope is 2 and the y intercept is -5. Graph this line and shade above the line for the solution. :)

5 0

4 years ago

Use the quadratic formula to solve the equation 25x^2-30x+25=0

Reika [66]

Answer: $x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}$

Step-by-step explanation:

$25x^2-30x+25=0$

$x_{1,\:2}=\frac{-\left(-30\right)\pm \sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}}{2\cdot \:25}$

$\sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}$

$=\sqrt{30^2-4\cdot \:25\cdot \:25}$

$=\sqrt{30^2-2500}$

$=i\sqrt{2500-30^2}$

$=40i$

$x_{1,\:2}=\frac{-\left(-30\right)\pm \:40i}{2\cdot \:25}$

$x_1=\frac{-\left(-30\right)+40i}{2\cdot \:25},\:x_2=\frac{-\left(-30\right)-40i}{2\cdot \:25}$

$x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}$

8 0

3 years ago

Question 7(Multiple Choice Worth 1 points) (08.02 LC) Eva conducted a survey to find out the amount of time high schoolers spend

Lady bird [3.3K]

Answer:

The answer is "Option B".

Step-by-step explanation:

The difference between most time and also the least spending time on Internet surfing is 3 hours. Since we do not have charts for tables etc., only 3 can be used we need. A range is defined as the difference between the largest and the smallest amounts. The range between both the largest as well as the smallest is unique. In this reply, it tells us that the gap between most time and the fewer hours invested surfing the web is 3 hours.

In option A, it is wrong since the range has nothing to do with formulas. (Of course, the dividend with a divisor results in a quotient). Only subtraction and not division may be achieved.
In option C, when all surf for exactly one hour, it could take the largest time of 3 hours and 3 hours, the last time. Add it into the equation and the range of the data present would've been 0.
In option D, It is erroneous even as the range is not the mean, and the mean seems to be the average. We search for both the range, not the mean.

3 0

3 years ago