Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
For this case we have that by definition it is fulfilled:

Where:
a: It is the base
b: It is the exponent
So, if we have the following expression:
-6 to the power of 4, is equivalent to: 
So we have to:
-6: It is the base
4: It is the exponent
Answer:
-6: It is the base
4: It is the exponent
1 gallon = 3.78541 liters.
Multiply the number of gallons by 3.78541:
10 x 3.78541 = 37.8541 liters (round the answer as needed)
We have been given graph of circle V with radius 14 feet. We are asked to find the area of the circle V.
We will use area of circle formula to solve our given problem.
, where r represents radius of circle.
Upon substituting
in above formula, we will get:




Therefore, the area of the circle V is
square feet and option 'c' is the correct choice.