Ask question

Ask question

All categories

4 years ago

6

Peter decided to buy a new car. He made $2,460 down payment and took a 48-month loan the total amount of the car plus interest o

n the loan was 16560 how much did Peter have to pay each month

1 answer:

n200080 [17]4 years ago

3 0

Peter's monthly payments totaled (16560 - 2460) = 14,100, so each of the 48 monthly payments was
$14,100/48 = $293.75

You might be interested in

Randy filled out a deposit slip today. He deposited two checks for $123.17 and $34.68 and took out $50 in cash

erica [24]

What he has left in the bank is here :

(123.17 + 34.68) - 50 = 107.8

He still has $107.8 left in the bank and he has $50 in his pocket.

I hoped I helped!

7 0

4 years ago

Read 2 more answers

Young's modulus is a quantitative measure of stiffness of an elastic material. Suppose that for aluminum alloy sheets of a parti

neonofarm [45]

Answer:

a1) $\mu_{\bar{X}} = 70$

a2) $\sigma_{\bar{X}} = 0.4$

b1) $\mu_{\bar{X}} = 70$

b2) $\sigma_{\bar{X}} = 0.2$

c) X is more likely to be within 1 GPa of 70 GPa in the random sample of part b because of the largeness in sample size and less scattering of data

Step-by-step explanation:

Mean value, $\mu = 70$

Standard deviation, $\sigma = 1.6$

a1) sample size, n = 16

Mean of the sampling distribution of the sample mean = mean value, i.e.

$\mu_{\bar{X}} = \mu\\\mu_{\bar{X}} = 70$

a2) The standard deviation of the sampling distribution of the sample mean

$\sigma_{\bar{X}} = \frac{\sigma}{\sqrt{n} } \\\sigma_{\bar{X}} = \frac{1.6}{\sqrt{16} }\\\sigma_{\bar{X}} = 0.4$

b1) For sample size, n = 64

Mean of the sampling distribution of the sample mean = mean value, i.e.

$\mu_{\bar{X}} = \mu\\\mu_{\bar{X}} = 70$

a2) The standard deviation of the sampling distribution of the sample mean

$\sigma_{\bar{X}} = \frac{\sigma}{\sqrt{n} } \\\sigma_{\bar{X}} = \frac{1.6}{\sqrt{64} }\\\sigma_{\bar{X}} = 0.2$

c) X is more likely to be within 1 GPa of 70 GPa in the random sample of part b because it has a larger sample size, hence a decrease in the variability. This makes us easily determine the position of the sample around the population mean

5 0

4 years ago

G=h(t) + p(c) is an equation that represents the gross pay of a server: Gross pay = hourly wage (time worked) + percent tip (cos

rusak2 [61]

Answer:

$105.5 for 16 hours at $6.59 per hour

Step-by-step explanation:

form the equation given, G=h(t) + p(c)

where G=Gross pay,

h= hourly wage

t=time worked

p=percent tip

c=cost of customer meals

we determine the gross pay by first determining the independent variables

h=$4.25, t=16 hours,

$p=15%of c\\p=\frac{15}{100}*250 \\p=37.5$

if we substitute values, we arrive at

$G=h(t)+p(c)\\G=4.25(16)+37.5\G=68+37.5\\G=105.5$

to determine the per hour gross pay we have

105.5/16

hourly gross pay,G=$6.59

3 0

3 years ago

suppose that during one period of extreme cold the average daily temp decreased 1 1/2 Fahrenheit each day how many days did it t

Nina [5.8K]

Answer:

The temperature decreased by 9 °F in <u>6 days.</u>

Step-by-step explanation:

Let the number of days it takes for the temperature to decrease by 9 °F be $x$ .

Given:

Average daily temperature decreases by $1\frac{1}{2}$ °F.

Decrease of temperature in 1 day = $1\frac{1}{2}$ = 1.5 °F.

∴ Decrease in temperature in x days is $1.5x$ .

Now, as per question, decrease in temperature in 'x' days is 9 °F.

Therefore, $1.5x=9$

$x=\frac{9}{1.5}$

$x=6$

Therefore, the temperature decreased by 9 °F in 6 days.

7 0

3 years ago

What is the value of k and why

gayaneshka [121]

Answer:

b is the answer

Step-by-step explanation:

8 0

3 years ago