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Charra [1.4K]
3 years ago
7

The bird house in your friend's yard casts a shadow that is 14 feet long. Your friend is 5 feet tall and casts a shadow that is

3.5 feet long. What is the height of the bird house?

Mathematics
2 answers:
Kazeer [188]3 years ago
4 0

Answer:

20 feet high

Step-by-step explanation:

Do the work

RideAnS [48]3 years ago
3 0

Answer:

Bird house is 20 ft. high.

Step-by-step explanation:

Let the height of the bird house is h feet high casts a shadow of 14 ft long.

My friend is 5 feet high and casts a shadow of 3.5 feet.

Now we see both the triangles Δ ABC and Δ XYZ are similar.

By the similar triangles theorem sides opposite to the corresponding angles will be in the same ratio.

\frac{5}{h}=\frac{3.5}{14} (from similar triangles ABC and XYZ)

h=\frac{14\times5}{3.5}=\frac{70}{3.5}=20 ft.

Therefore bird's house is 20 feet high.

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Insert 80 into the equation
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Sphinxa [80]

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<h3>Thomas's age is 24.</h3>
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The average daily high temperature in °C) in Karachi, Pakistan, on the tth day of the year is
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Answer:

The highest would be 34 degrees Celsius and the lowest would be 24 degrees Celsius.

Step-by-step explanation:

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3 0
3 years ago
Variable y varies directly with variable x. If x = 12, then y = 3. What is the value of y
Monica [59]

Answer:

<h2>y = 2</h2>

Step-by-step explanation:

To find the value of y when x = 8 we must first find the relationship between the two variables.

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Hope this helps you

5 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

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(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
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