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stich3 [128]
3 years ago
6

which has greater cenetic energy a car traveling 30.0 km/hr or one twice as heavy traveling at 15 km/hr?​

Mathematics
1 answer:
iVinArrow [24]3 years ago
8 0

Answer:

30 km/h car

Step-by-step explanation:

From analysis the   car traveling at 30 km/h has greater kinetic energy

we can deduce it from the expression of kinetic energy which is

KE=\frac{1}{2} mv^2

Assuming the mass m= 1 kg

 

For the 30 km/h

KE=\frac{1}{2}*1*30^2 \\\\KE=\frac{1}{2}*1*900\\\\\KE=450 J

   

For the 15 km/h

KE=\frac{1}{2}*2*15^2 \\\\ KE=\frac{1}{2}*2*225 \\\\\ KE=\frac{1}{2}*450 J\\\\\ KE=225 J

Though the kinetic energy is a function of mass and velocity, but from our analysis the faster moving object has more KE

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5/6k=-20 what is the correct answer ??
damaskus [11]
<span>5/6k=-20

k=-24

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4 0
3 years ago
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How many ways are there to select a 5-card hand from a regular deck such that the hand contains at least one card from each suit
Snezhnost [94]

Answer:

There are 685464 ways of selecting the 5-card hand

Step-by-step explanation:

Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.

In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have {13 \choose 2} = 78 possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.

This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.

6 0
3 years ago
In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day
nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

So

P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

P(A \cap B) = 0.42*0.25 = 0.105

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

P(B|A) = \frac{0.105}{0.33} = 0.3182

31.82% probability that this day would be a winter day

6 0
3 years ago
Solve number 8 (geometry)
ANEK [815]

Answer:

x = 50

Step-by-step explanation:

the word bisects means that it cuts in half (this is how I understand it, not the official definition :D)

so that means

\angle XAB =\angle BAY\\\\2x=100\\\\x=50

3 0
3 years ago
. 40% of 60 students of a class are good at art. How many students are not good at art? *​
melisa1 [442]

Answer:

36

Step-by-step explanation:

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60% not good at art.

60*60% = 60*6/10 = 6*6 = 36

6 0
2 years ago
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