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DerKrebs [107]
3 years ago
11

A sample of n = 4 scores is selected from a population with m = 40 with s = 8, and the sample mean is M = 43. What is the standa

rd error for the sample mean?
Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0
Standard error (SE)
se=   \frac{s}{ \sqrt{n} }
Or

se =  \sqrt{ \frac{ {s}^{2} }{n} }

Therefore, SE of the mean = (8)/(2) =4
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In the diagram below, what is the approximate length of the minor arc xy ?
siniylev [52]

Answer: 48 centimeters

Step-by-step explanation:

4 0
3 years ago
marla has 4.55 in dimes and quarters. if she ha s7 more quarters than dimes, how many quarters doe she have?
Jlenok [28]

Answer:

number of dimes is 8

number of quarters is 15

Step-by-step explanation:

let 'd' = number of dimes

let 'd+7' = number of quarters

.10d + .25(d + 7) = 4.55

.10d + .25d + 1.75 = 4.55

.35d = 2.80

d = 8

q = 7 + 8

8 0
3 years ago
Which of the following functions represents a cell phone bill if there is a monthly charge of 20 dollars plus 6 cents for each m
pychu [463]

Answer:

f(x)=20+0.06x

Step-by-step explanation:

3 0
3 years ago
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
If f(x) = -7x + 1 and g(x) = Square root of x-5,<br> what is (fºg)(41)?
Ghella [55]

This is similar to the other question you posted. Follow the same steps as before.

First find g(41).

g(41) = sqrt{x - 5}

g(41) = sqrt{41 - 5}

g(41) = sqrt{36}

g(41) = 6

We now find f(6).

f(6) = -7(6) + 1

f(6) = -42 + 1

f(6) = -41

Answer:

(fºg)(41) = -41

Did you follow?

6 0
3 years ago
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