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2 years ago

Help me fast ..................

Mathematics

1 answer:

Kisachek [45]2 years ago

7 0

If two angles and included side of one triangle are equal to two angles and the included side of the other triangle , then the two triangles are congruent (ASA rule).

in figure

consider triangle ABD and ACD
Angle BAD = angle CAD
AB = AC
Angle B = angle C
triangle ABD congruent to Triangle ACD ( by ASA rule)

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F(x)= x^2 what is g(x)?

sattari [20]

Answer:

"C"

Step-by-step explanation:

6 0

2 years ago

Help me plz, i’d love u forever

Sergio039 [100]

1. We know that 1 feet = 12 inches

let x be a number of inches, which when added to 18 inches will give 7 feet

18 inches + x inches = 7 feet

18 inches + x inches = 84 inches [1 feet = 12 inches]

x inches = 84 inches - 18 inches

x inches = 66 inches

2. We know that 1 mile = 1760 yards

let x be the number of yards, when added to 2000 yards will be equal to 2 miles

2000 yards + x yards = 2 miles

2000 yards + x yards = 3520 yards

x yards = 1520 yards

3. We know that 1 feet = 12 inches

Number of feet = Given number of inches / 12

Number of feet = 108 / 12

Number of feet = 9 ft.

4. We know that 1 mile = 5280 feet

let x be the number of feet, when added to 8800 feet. will be equal to 8 miles

8800 feet + x feet = 8 miles

8800 feet + x feet = 42240 feet [1 mile = 5280 feet]

x feet = 42240 - 8800

x feet = 33440 ft.

5. We know that 12 inches = 1 feet

let x be the number of inches, when added to 37 inches, will be equal to 5 feet

37 inches + x inches = 5 feet

37 inches + x inches = 60 inches [12 inches = 1 feet]

x inches = 23 inches

6. We know that 1 yard = 3 feet

So, (number of yards)*3 = (number of feet)

Number of yards = number of feet / 3

Number of yards = 73 / 3 = 24.33 yards

7. We know that 1 yard = 3 feet

let x be the number of feet added to 15 feet to make 9 yards

15 feet + x feet = 9 yards

15 feet + x feet = 27 feet [1 yard = 3 feet]

x feet = 12 ft

8. We know that 1 mile = 1760 yards

let x be the number of yards remaining to reach 4 miles

3000 yards + x yards = 4 miles

3000 yards + x yards = 7040

x yards = 4040 yards

9. We know that 1 yard = 3 feet

So, number of yards * 3 = number of feet

replacing the values:

number of yards*3 = 114

number of yards = 114/3

number of yards = 38 yards

10. We know that 1 mile = 5280 feet

let x be the number of feet that must be added to 9000 feet to make 3 miles

x feet + 9000 feet = 3 miles

x feet + 9000 feet = 15840 feet

x ft = 6840 ft

11. We know that 12 inches = 1 feet

let x be the number of inches that must be added to 46 inches to get a length of 9 feet

46 inches + x inches = 9 feet

46 inches + x inches = 108 inches

x inches = 108 - 46 inches

x inches = 62 inches

12. We know that 1 mile = 1760 yards

let x be the number of yards that must be added to 3500 yards to make 2 miles

3500 yards + x yards = 2 miles

3500 yards + x yards = 3520 yards

x = 20 yards

13. We know that 1 ft = 12 inches

So, number of feet * 12 = number of inches

number of feet = number of inches / 12

number of feet in 252 inches

Number of feet = 252/12

Number of feet = 21 ft

14. We know that 1 mile = 5280 feet

let x be the number of feet, when added to 6500 feet, will be equal to 2 miles

x ft + 6500 ft = 2 miles

x ft + 6500 ft = 10560 ft

x ft = 4060 ft

15. We know that 1 mile = 5280 feet

let x be the number of feet, when added to 4500 feet, will be equal to 1 mile

x ft + 4500 ft = 1 mile

x ft + 4500 ft = 5280 ft

x ft = 780 ft

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2 years ago

Order the number from greatest to least 3 1/3,3.34,300%

Liula [17]

Answer:

3.34, 3 1/3 300%

6 0

3 years ago

Read 2 more answers

Please help! I need to show my work

Minchanka [31]

You can graph the 4 points.
Notice that sides AB and CD are horizontal, so they are parallel with different lengths.
Sides BC and Ad are not parallel.
A quadrilateral with two parallel sides and two non-parallel sides is a trapezoid.

4 0

3 years ago

B(n) = b(n − 1) - 7

xxMikexx [17]

Answer:

b=-7

Step-by-step explanation:

if you were supposed t solve for something else just comment and i'll come back :)

(next time state what ur solving for)

3 0

3 years ago

Help me fast ..................​

Help me fast ..................