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2 years ago

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Mathematics

1 answer:

Kisachek [45]2 years ago

7 0

If two angles and included side of one triangle are equal to two angles and the included side of the other triangle , then the two triangles are congruent (ASA rule).

in figure

consider triangle ABD and ACD
Angle BAD = angle CAD
AB = AC
Angle B = angle C
triangle ABD congruent to Triangle ACD ( by ASA rule)

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HELP!! Pls show work

Art [367]

Plug in -6 for a and -5 for b

3(-6)^2 - 4(-5)
3(36)+20
108+20
=120

5 0

3 years ago

Need help on math You have a meal at a restaurant. The sale tax is 8% . You leave a tip for the waitress that is 20% of the pret

DerKrebs [107]

Answer: $18

Step-by-step explanation:

Let x= Pretax price of the meal.

Given: Sales tax = 8%

Tip percent = 20%

As per given ,

Amount spent = ( Pretax price) + (Sales tax ) of (Pretax price) + (Tip percent)of (Pretax price)

= x+ 8% of x + 20% of x

= x +0.08+0.20x

= 1.28x

∵ Amount spent = $23.04

So,

$1.28x=23.04\\\\\Rightarrow\ x=\dfrac{23.04}{1.28}\\\\\Rightarrow\ x=18$

Hence, the pretax price of the meal= $18.

4 0

2 years ago

PLEASE HELP ME ANSWER IF YOU KNOW!!!!!!!!!1111

Novay_Z [31]

Answer:

20,000 divided by 4,250

Step-by-step explanation:

5 0

3 years ago

Find the number of terms, n, in the arithmetic series whose first term is 13, the common difference is 7, and the sum is 2613.

siniylev [52]

Answer:

Step-by-step explanation:

Recall that the sum of an arithmetic series is given by:

$\displaystyle S = \frac{n}{2}\left(a + x_n\right)$

Where n is the number of terms, a is the first term, and x_n is the last term.

We know that the initial term a is 13, the common difference is 7, and the total sum is 2613. Since we want to find the number of terms, we want to find n.

First, find the last term. Recall that the direct formula for an arithmetic sequence is given by:

$x_n=a+d(n-1)$

Since the initial term is 13 and the common difference is 7:

$x_n=13+7(n-1)$

Substitute:

$\displaystyle S = \frac{n}{2}\left(a + (13+7(n-1)\right)$

We are given that the initial term is 13 and the sum is 2613. Substitute:

$\displaystyle (2613)=\frac{n}{2}((13)+(13+7(n-1)))$

Solve for n. Multiply both sides by two and combine like terms:

$5226 = n(26+7(n-1))$

Distribute:

$5226 = n (26+7n-7)$

Simplify:

$5226 = 7n^2+19n$

Isolate the equation:

$7n^2+19n-5226=0$

We can use the quadratic formula:

$\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = 7, b = 19, and c = -5226. Substitute:

$\displaystyle x =\frac{-(19)\pm\sqrt{(19)^2-4(7)(-5226)}}{2(7)}$

Evaluate:

$\displaystyle x = \frac{-19\pm\sqrt{146689}}{14} = \frac{-19\pm 383}{14}$

Evaluate for each case:

$\displaystyle x _ 1 = \frac{-19+383}{14} = 26\text{ or } x _ 2 = \frac{-19-383}{14}=-\frac{201}{7}$

We can ignore the second solution since it is negative and non-natural.

Therefore, there are 26 terms in the arithmetic series.

Our answer is A.

6 0

2 years ago

5 students each brought in 8 boxes with 10 pencils per box and 10 students each brought in 8 boxes with 5 pencils per box how ma

Viefleur [7K]

Answer:

800 pencils

Step-by-step explanation:

because if 5students brought in a set of 8 box's with ten in it you get 80 times 5 you get 400 then you add the ten students that brought in a set of 40 each which is another 400 so400 +400= 800

3 0

2 years ago

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