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mylen [45]
2 years ago
10

Find the solution to each equation.

Mathematics
1 answer:
Alex2 years ago
7 0

Answer:

k = 16

p = 21

m = 24

c = 23

g = 18

Step-by-step explanation:

All you had to do was divide the product by the number with the variable

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If the risk-free rate is 7 percent, the expected return on the market is 10 percent, and the expected return on Security J is 13
Lelu [443]

Answer:

0.02 or 2% = Beta

Step-by-step explanation:

Given that,

Risk-free rate = 7 percent

Expected return on the market = 10 percent

Expected return on Security J = 13 percent

Therefore, the beta of Security J is calculated as follows;

Expected return on Security J = Risk-free rate + Beta (Expected return on the market - Risk-free rate)

13 percent = 7 percent + Beta (10 percent - 7 percent)

0.13 - 0.07 = 0.03 Beta

0.06 = 0.03 Beta

0.06 ÷ 0.03 = Beta

0.02 or 2% = Beta

6 0
3 years ago
Point S is on line segment RT. Given RT=4x, ST = 5x-10, and RS = 6 determine the numerical length of ST.
Art [367]

Answer:

ST=10

Step-by-step explanation:

8 0
3 years ago
Solve for p.<br><br> 2(p + 1) = 18
n200080 [17]

Answer:

p = 8

Step-by-step explanation:

Subtract 18 from behind the equal sign to cancel it out. This leaves you with 2(p+1)- 18= 0.

Next you'll need to pull out the terms to work with the beginning of the problem. 2(p+1)- 18= 0 would turn into 2p - 16  = 2(p - 8).

This would leave you with 2= 0, but that's not true so continue on to the variable.

So p - 8= 0 making the answer p = 8

7 0
3 years ago
Beginning at sunrise, the temperature rose 2.8 degrees per hour.
Dahasolnce [82]
19.18 / 2.8 = 6.85

So answer is D.6.850 h
6 0
3 years ago
Read 2 more answers
Can someone help me out with number 2?
Norma-Jean [14]
\sin255^o=\sin(300^o-45^o)=\sin300^o\cos45^o-\cos300^o\sin45^o= \\\\=- \frac{ \sqrt{3} }{2}\cdot  \frac{ \sqrt{2} }{2}- \frac{1}{2} \cdot  \frac{ \sqrt{2} }{2}=-      \frac{ \sqrt{6} }{4} -  \frac{ \sqrt{2} }{4}=  -\frac{  \sqrt{6}+\sqrt{2} }{4}

5 0
3 years ago
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