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2 years ago

What is the value of X

Mathematics

1 answer:

Ulleksa [173]2 years ago

7 0

Answer:

B. 8

Step-by-step explanation:

The sum of all exterior angles of pentagon is equal to 360°. There are such exterior angles: 62°, 66°, 77°, 59°, (12x)°. Thus, the sum

$62^{\circ}+66^{\circ}+77^{\circ}+59^{\circ}+(12x)^{\circ}=360^{\circ},\\ \\264^{\circ}+(12x)^{\circ}=360^{\circ},\\ \\(12x)^{\circ}=360^{\circ}-264^{\circ},\\ \\(12x)^{\circ}=96^{\circ},\\ \\x^{\circ}=8^{\circ}.$

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What is the solution set of the equation using the quadratic formula? x2+6x+10=0 {−3+2i,−3−2i} {−6+2i,−6−2i} {−3+i,−3−i} {−2i,−4

olga2289 [7]

Answer:

The solution set of the quadratic function $x^{2}+6\cdot x +10$ is $\{-3+i,-3-i\}$ .

Step-by-step explanation:

Let be a second-order polynomial (quadratic function) is standard form and equalized to zero:

$a\cdot x^{2}+b\cdot x + c = 0$

Its roots can be determined by the Quadratic Formula in terms of its polynomial coefficients, which states that:

$x_{1,2} = \frac{-b\pm\sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}$

Given that $a = 1$ , $b = 6$ and $c = 10$ , the roots of the polynomial are, respectively:

$x_{1,2} = \frac{-6\pm \sqrt{6^{2}-4\cdot (1)\cdot (10)}}{2\cdot (1)}$

$x_{1,2} = -3\pm i$

$x_{1} = -3+i$

$x_{2} = -3 -i$

The solution set of the quadratic function $x^{2}+6\cdot x +10$ is $\{-3+i,-3-i\}$ .

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Read 2 more answers

I need help on this Question.!

OLga [1]

Answer:

see below

Step-by-step explanation:

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Using cross products

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Step-by-step explanation:

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