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Alex_Xolod [135]
4 years ago
13

What the answer to this question

Mathematics
1 answer:
Sonja [21]4 years ago
3 0

To solve this, you need to isolate/get the variable "u" by itself in the inequality:            u = unknown number

2u - 3 < 1       Add 3 on both sides

2u - 3 + 3 < 1 + 3

2u < 4        Divide 2 on both sides to get "u" by itself

u < 2       (u is any number less than 2)

When the inequality sign is >/< (greater than/less than), the dot/endpoint is an open/unfilled circle.

When the inequality sign is ≥/≤ (greater than or equal to/less than or equal to), the dot is a closed/filled circle.

u < 2        

Start making a ray by placing an open circle on 2(click on the dot/endpoint to change it to be open if it isn't already), then have the ray point left where the numbers would be decreasing because "u" is any number less than 2. If you can place the end of the ray at the end of the number line.

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Answer: 2.76 g

Step-by-step explanation:

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\sigma=\sqrt{\dfrac{\sum(x_i-\overline{x})^2}{n}}

The given data values : 560 g, 562 g, 556 g, 558 g, 560 g, 556 g, 559 g, 561 g, 565 g, 563 g.

Then,  \overline{x}=\dfrac{\sum_{i=1}^{10} x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{560+562+556+558+560+556+559+561+565+563}{10}\\\\\Rightarrow\ \overline{x}=\dfrac{5600}{10}=560

Now, \sum_{i=1}^{10}(x_i-\overline{x})^2=0^2+2^2+(-4)^2+(-2)^2+0^2+(-4)^2+(-1)^2+1^2+5^2+3^2\\\\\Rightarrow\ \sum_{i=1}^{10}(x_i-\overline{x})^2=76

Then, \sigma=\sqrt{\dfrac{76}{10}}=\sqrt{7.6}=2.76

Hence, the  standard deviation of his measurements = 2.76 g

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Step-by-step explanation: Hope this helps :)

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