Answer:
no guaranteed classification
Step-by-step explanation:
We know that the quadrilateral has two pairs of congruent sides. Both a rectangle and a parallelogram have two pairs of congruent sides. The difference between them is their angles. But we don't know anything about the angles in the figure, so we cannot know which kind it is.
Add 1, then add 2, then add 3, then 4, then 5, then 6.
Answer:
Step-by-step explanation:
First, isolate the variables onto one side of the equation.
2x + 3 = x - 4
(subtract x)
x + 3 = -4
Then, remove any remaining numbers.
(subtract 3)
x = -7
I hope this helps!
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:

Step-by-step explanation:
P, A, and R are collinear.
PR = 54


To solve for the numerical length of PR, let's generate an equation to find the value of x.
According to the segment addition postulate:

(substitution)
Solve for x

Combine like terms


Add 2 to both sides


Divide both sides by 7



Plug in the value of x into the equation

