Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
X/2=8/9 | *2
x=16/9≈ 1,78
2. 1 $.........1,09 Euro
x$...........157 Euro
x=157*1/1,09≈144,04 $
0.08 is larger because it can also be written as 0.080, and 80 is larger than 76.
Answer:
4x^3+x+7
Step-by-step explanation:
Step-by-step explanation:
no
because it will become
3(3)>9
9>9
it must be more than 9 unless the symbol is
