Answer:
you have to use the slope equation, which is (y2-y1) / (x2-x1)
3. (5-0)/(1 -(-8))
5/1+8
5/9
4. (3-3)/(-4 -8)
0/-12
the slope is 0
6. (-2-8)/(1-0.5)
-10/0.5
-20
7. (7-(-1))/ (4-4)
7+1/0
8/0
the slope is undefined
One cat has four paws, so there are 120/4=30 cats. If a "set" of cats is two uncool cats and three cool cats, there are five cats in a set, so there are 30/5=6 sets. Since each of the six sets contains three cool cats, there are 18 cool cats in the family.
The answer is less than or equal to -4. Because -4+8=4
What are the lower and upper quartiles of this data 122,164,71,98,84,147,114,111,98,85,104,71,77
RSB [31]
Lower quartile = 80.5
Upper quartile = 118
Answer:
71
Step-by-step explanation:
8²=64
64+7=71
I hope this helps!
