Answer:
Absolute/extreme minimum at (-4,-2).
Step-by-step explanation:
Look at D. y=2(x+4)^2-2. Compare this to y = a(x-h)^2 + k. Through this comparison we see that h = -4 and k = -2.
Therefore, the vertex of the graph is at (-4,-2). The graph opens up. Therefore, (-4,-2) is the absolute minimum that y can have.
