Question

What is the pH of a 8.7 x 10^-12 M OH- solution ? pH= ?

Answer 1

Answer: The pH of the solution is 2.94

Explanation:

pH is the measure of acidity or alkalinity of the solution.

Given $OH^-$ concentration,first we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (8.7\times 10^{-12})$

$pOH=11.06$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-11.06=2.94$

Therefore, the pH of the solution is 2.94.

Answer 2

PH=14-pOH

pOH=-lg[OH⁻]

pH=14+lg[OH⁻]

pH=14+lg(8.7*10⁻¹²)=14-11.06=2,94