can be oxidized to form carbon dioxide
Explanation:
Oxygen is important in the oxidation of glucose because it can be oxidized to form carbon dioxide. Oxidation of glucose involves the reaction of oxygen with glucose in a process called respiration. This gives a product of water, carbon dioxide and energy which is stored as ATP.
- Oxidation involves the addition of oxygen.
- Any specie that undergoes oxidation, is a reducing agent and it is said to be oxidized.
- Oxygen is oxidized to form carbon dioxide and water.
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Respiration and photosynthesis brainly.com/question/3437832
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Answer:
Yes it is B,D.
Explanation:
Each box represents an element and contains its atomic number, symbol, average atomic mass, and (sometimes) name. The elements are arranged in seven horizontal rows, called periods or series, and 18 vertical columns, called groups.
No
Magnesium Chloride is MgCl2
The method I use to name ionic compounds is 'swap and drop'
Mg oxidation number is +2 and Cl oxidation number is -1
Mg^2+ Cl^-1
'swap'
Mg^1 Cl^2
'drop'
MgCl2
Answer:
A. Occur in gaseous and liquid state
Explanation:
The choice that is not a characteristic of minerals is that minerals occur in gaseous and liquid state.
All minerals are solid inorganic compounds.
- A mineral is an inorganic compound that is formed naturally.
- They have a definite and specific chemical composition.
- Minerals are the building blocks of rocks.
- When minerals aggregates together, they form different rock types.
- There is no known mineral that is in fluid state.
- All minerals are solids.
- Examples are quartz, kaolinite, gypsum e.t.c
Answer:
25.6g de HF son producidos
Explanation:
<em>...¿Cuánto HF es producido?</em>
Para resolver este problema debemos convertir la masa de cada reactivo a moles usando su masa molar. Como la reacción es 1:1, el reactivo con menor número de moles es el reactivo limitante. Con las moles del reactivo limitante podemos obtener las moles de HF y su masa así:
<em>Moles CaF2:</em>
Masa molar:
1Ca = 40g/mol
2F = 19*2 = 38g/mol
40+38 = 78g/mol
50g CaF2 * (1mol/78g) = 0.641 moles CaF2
<em>Moles H2SO4:</em>
Masa molar:
2H = 2g/mol
1S = 32g/mol
4O = 64g/mol
98g/mol
100g H2SO4 * (1mol / 98g) = 1.02 moles H2SO4
Como las moles de CaF2 < Moles H2SO4: CaF2 es reactivo limitante.
<em>Moles HF usando la reacción:</em>
0.641 moles CaF2 * (2mol HF / 1mol CaF2) = 1.282 moles HF
<em>Masa HF:</em>
Masa molar:
1g/mol + 19g/mol = 20g/mol
1.282 moles HF * (20g/mol) =
<h3>25.6g de HF son producidos</h3>
