common difference, d = -3
f1 = -13
An arithmetic sequence f(n) = f1 + d(n - 1)
so f(n) = -13 - 3(n - 1)
f(46) = -13 - 3(46-1) = -13 -3(45) = -13 - 135 = -148
Answer:
f(46) = - 148
Answer:
x= 4/3
Step-by-step explanation:
Answer: 0.6827
Step-by-step explanation:
Given : Mean IQ score : 
Standard deviation : 
We assume that adults have IQ scores that are normally distributed .
Let x be the random variable that represents the IQ score of adults .
z-score : 
For x= 90

For x= 120

By using the standard normal distribution table , we have
The p-value : 

Hence, the probability that a randomly selected adult has an IQ between 90 and 120 =0.6827
All you have to do is plug in.
x = 1 , y= 8
3x+5=y
3(1) + 5 = 8
3+5 = 8
8=8
They are both equal, yes. The coordinates work out in the equation. Both sides are equal so the coordinates work. The answer is yes.
Answer:
y = 1/2x - 7
Step-by-step explanation:
y = 1/2x + b
-4 = 1/2(6) + b
-4 = 3 + b
-7 = b