Split
into two component segments,
and
, parameterized by
![\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)](https://tex.z-dn.net/?f=%5Cmathbf%20r_1%28t%29%3D%281-t%29%280%2C0%29%2Bt%286%2C1%29%3D%286t%2Ct%29)
![\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)](https://tex.z-dn.net/?f=%5Cmathbf%20r_2%28t%29%3D%281-t%29%286%2C1%29%2Bt%287%2C0%29%3D%286%2Bt%2C1-t%29)
respectively, with
, where
.
We have
![\mathrm d\mathbf r_1=(6,1)\,\mathrm dt](https://tex.z-dn.net/?f=%5Cmathrm%20d%5Cmathbf%20r_1%3D%286%2C1%29%5C%2C%5Cmathrm%20dt)
![\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt](https://tex.z-dn.net/?f=%5Cmathrm%20d%5Cmathbf%20r_2%3D%281%2C-1%29%5C%2C%5Cmathrm%20dt)
where ![\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt](https://tex.z-dn.net/?f=%5Cmathrm%20d%5Cmathbf%20r_i%3D%5Cleft%28%5Cdfrac%7B%5Cmathrm%20dx%7D%7B%5Cmathrm%20dt%7D%2C%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dt%7D%5Cright%29%5C%2C%5Cmathrm%20dt)
so the line integral becomes
![\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_C%28x%2B6y%29%5C%2C%5Cmathrm%20dx%2Bx%5E2%5C%2C%5Cmathrm%20dy%3D%5Cleft%5C%7B%5Cint_%7BC_1%7D%2B%5Cint_%7BC_2%7D%5Cright%5C%7D%28x%2B6y%2Cx%5E2%29%5Ccdot%28%5Cmathrm%20dx%2C%5Cmathrm%20dy%29)
![=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt](https://tex.z-dn.net/?f=%3D%5Cdisplaystyle%5Cint_0%5E1%286t%2B6t%2C%286t%29%5E2%29%5Ccdot%286%2C1%29%5C%2C%5Cmathrm%20dt%2B%5Cint_0%5E1%28%286%2Bt%29%2B6%281-t%29%2C%286%2Bt%29%5E2%29%5Ccdot%281%2C-1%29%5C%2C%5Cmathrm%20dt)
![=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6](https://tex.z-dn.net/?f=%3D%5Cdisplaystyle%5Cint_0%5E1%2835t%5E2%2B55t-24%29%5C%2C%5Cmathrm%20dt%3D%5Cfrac%7B91%7D6)
To find the experimental probability, you will add the outcomes that resulted in even number and make that a ratio to the total number of outcomes.
<u>(12 + 14 + 18)</u>
(13 + 12 + 12 +14 + 11 + 18)
44/80 = 0.55
0.55 = 55%
The answer is choice D.
Answer:
72 alligators, 128 turtles
Step-by-step explanation:
When you put the words into the form of an equation, with a being alligators, you get
3a-16=200
So you have to do 'letters left numbers right'. This gives you
3a=216
Now you have to divide. 216 divided by 3 equals 72. So there are 72 alligators. 200 minus 72 equals 128, so there are 128 turtles
Answer is in the pic above. Theorems used:
Exterior angle theorem
Inscribed angle theorem.
![\angle EBF=32.5°](https://tex.z-dn.net/?f=%20%5Cangle%20EBF%3D32.5%C2%B0)