If the areas of two equilateral triangles are 27 yd² and 75 yd², then the ratio of these areas is 27/75 = 9/25
If the ratios of the areas are 9:25, then their similarity ratio and the ratio of their perimeters is √9:√35 = 3:5.
3 : 5; 3 : 5 <==ANSWER
Hey there! :D
The congruence marks on the trapezoid make the angles congruent. This makes opposite angles supplementary. (Because all the angles in a trapezoid add up to 360 degrees)
12x-31+6x-5= 180
18x-36= 180
Add 36 to both sides.
18x= 216
Divide both sides by 18.
x= 12
You can just plug that in to find m<H.
6x-5
6(12)-5
72-5
m<H= 67
I hope this helps!
~kaikers
The missing reason to complete Hector's proof is
<span>Corresponding Parts of Congruent Triangles Are Congruent
It's been established in the previous statement that triangle LNO and triangle PNM are congruent by the AAS Postulate.
The proof
</span>Corresponding Parts of Congruent Triangles Are Congruent
is comprehensive.
I believe the answer is 5. I multiplied 5 to -4 and that’s -20 and I’m guessing since slope-intercept form is y=Mx+b I’m thinking b=4 and the slope being 5 matches the output. -16=5(-4)+4
