Answer:
19.8 and 8/(sin(theta))+ 6/(cos(theta))
Step-by-step explanation:
If you make a table you can see that L_1 + L_2 gets larger as you increase theta prom pi/2 and decrease theta from pi/2. This means that pi/2 is the theta that will yield the smallest length for the ladder. Plugging this into L_1 + L_2 you get 19.8 (rounded to the nearest hundred)
C = 8/(sin(theta))+ 6/(cos(theta))
Answer:
160π cm²
Step-by-step explanation:
The area of the shaded region is
area of outer circle - area of inner circle
A = πr₁² - πr₂²
r₁ is the radius of the outer circle = 10 + 3 = 13 cm
r₂ is the radius of the inner circle = 3 cm
A = π × 13² - π × 3²
= π(169 - 9) = 160π cm² ≈ 502.65 cm² ( to 2 dec. places )
Answer:
-5x -12
Step-by-step explanation:
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