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SOVA2 [1]
3 years ago
9

Circle D circumscribes ABC and ABE. Which statements about the triangles are true?

Mathematics
2 answers:
OleMash [197]3 years ago
7 0
<span>Circle D circumscribes ABC and ABE, The statements that best describe the triangles are: 
</span><span>Statement I: The perpendicular bisectors of ABC intersect at the same point as those of ABE.
Statement II: The distance from C to D is the same as the distance from D to E. Hence, each of them (CD and DE) is a radius of the given circle.
So, the answer is the second option, I and II.

</span>
sladkih [1.3K]3 years ago
3 0

Answer:

I and II

Step-by-step explanation:

Statement I: The perpendicular bisectors of ABC intersect at the same point as those of ABE.

Statement 1 is true because the perpendicular bisectors intersect at the center of the circumcircle.

Since the two triangles have the same circumcircle, therefore, their perpendicular bisectors intersect at the same point. So statement I is true.

Statement II: The distance from C to D is the same as the distance from D to E.

Since they both, that is distance from C to D and the distance from D to E represent the radius of the circle therefore, they both are equal in length.

Therefore, only I and II are correct.

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22

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22

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3 years ago
Four more than seven times a number is 12.” Write an equation that represents the statement. Then solve.
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7x + 4 = 12

7x = 12-4

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4 years ago
Charlie invests £1200 at 3.5% per annum compound interest.
lbvjy [14]

Answer:

<h2>£1,330.46</h2>

Step-by-step explanation:

Using the compound interest formula A = P(1+\frac{r}{n} )^{nt}

A = amount compounded after n years

P = principal (amount invested)

r = rate (in %)

t = time (in years)

n = time used to compound the money

Given P =  £1200., r = 3.5%, t = 3years, n = 1 year(compounded annually)

A = 1200(1+0.035)^{3}\\ A = 1200(1.035)^{3}\\ A = 1200* 1.108717875\\A = 1,330.46

Value of Charlie's investment after 3 years is £1,330.46

6 0
3 years ago
*please help word problem* Adam and Barb had a used book sale over the weekend. Adam sold 4 hardcover books and ten paperbacks a
vekshin1

Let us assume charge for a hardcover book = $ h

And charge for a paperback = $ p.

Adam sold 4 hardcover books and 10 paperbacks and earned $64.

So, we can setup an equation by using above statement.

4h + 10p = 64        -------------equation(1)

Barb sold 5 hardcover books and 7 paperbacks and made $58.

So, we can setup another equation by using above statement.

5h + 7p = 58         -------------equation(2)

Let us solve equation(1) and eqation (2) by elimination method.

Multiplying first equation by -5 and second equation by 4 and adding, we get

-20h -50p = -320

20h +28p =  232

___________________

    -22p = -88

Dividing both sides by -22, we get

-22p/-22 = -88/-22

p=4.

Plugging p=4 in first equation.

4h + 10(4) = 64

4h +40 =64

Subtracting 40 from both sides, we get

4h = 24.

Dividing both sides by 4, we get

4h/4 = 24/4

h=6.

Therefore, they charge $6 for a hardcover and $4 for a paperback.

3 0
3 years ago
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