Help meeeeeeeeeeeeeeeeeeee

Natasha2012 [34]

$\frac{6}{10x^2} \div \frac{6}{10x^3-60x^2} = \frac{6}{10x^2} \cdot \frac{10x^3-60x^2}{6} =\frac{1}{10x^2} \cdot \frac{10x^2(x-6)}{1} =x-6$

5 0

3 years ago

Factor the expression using the GCF 32 - 48

Ivan

A GCF(or greates common factor) is exactly that the greates number taht can be used to divide both numbers. In this case 32 and -48 is 8 how do I know that because 8 times 4 is 32 and 8 times 6 is 48, now that you know that, I will leave unly the numbers that I used to multiply by 8 this would be 4 and 6, now that doesn't mean 8 is your GCF you have to check if your numbers can be simplified even more with another number well in this case yes 4 and 6 also share a common number ans this one is 2 4 divide by 2 is 2 and 6 divide by 2 is 3 now we are left with these numbers 2 and -3, now how do I know what was my GCF well this part is easy, just multiply the first number you used to divide times the second
E.J. in this case you would multiply 8 times 2 and this gives you 16... Now how do you know if this GCF is correct well multiply 16 times (2-3) usinf distributive property, 16 times 2 is 32 so we are good till now, and 16 times 3 is in fact -48 s our GCF is correct!!! this means 16(2-3) is our final answer

Hope this helps

4 0

3 years ago

Solve the equation 25x²+100x+200=0.

k0ka [10]

Answer:

$x = -2+2i ,x = -2-2i$

Step-by-step explanation:

given,

equation 25x²+100x+200=0

dividing the equation by 25 on both side

x²+4x+8=0

using

$x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x = \dfrac{-4\pm \sqrt{4^2-4\times 1\times 8}}{2}$

$x = \dfrac{-4+ \sqrt{4^2-4\times 1\times 8}}{2},x = \dfrac{-4-\sqrt{4^2-4\times 1\times 8}}{2}$

$x = \dfrac{-4+ \sqrt{-16}}{2},x = \dfrac{-4-\sqrt{-16}}{2}$

$x = \dfrac{-4+ 4i}{2},x = \dfrac{-4-4i}{2}$

$x = -2+2i ,x = -2-2i$

6 0

3 years ago

What is the slope of the line created by this equation?

Cloud [144]

Answer:

I think the answer will be:- m = $-\frac{2}{3}$ . I'm not sure.

6 0

3 years ago

An airplane has a total of 414 packets of crackers, pretzels, and peanuts available for passengers.

zhenek [66]

There is no question in Part A, but i do what i can.

Part A.
We know that:

n - number of packets of crackers
p - number of packets of pretzels

p = 2n+9

s - number of packets of peanuts

s = 3p = 3(2n+9) = 6n+27

So:

$n+p+s=414\\\\n+(2n+9)+(6n+27)=414\\\\9n+36=414\quad|-36\\\\9n=378\quad|:9\\\\\boxed{n=42}\\\\\\
p=2n+9=2\cdot42+9=\boxed{93}\\\\s=6n+27=6\cdot42+27=\boxed{279}$

There are 42 packets of crackers, 93 packets of pretzels and 279 packets of peanuts.

Part B.

x - number of rows with exactly 2 passengers
y - number of rows with exactly 3 passengers

and:

$\boxed{\begin{cases}x+y=48\\2x+3y=132\end{cases}}\\\\\\
\begin{cases}x+y=48\quad|\cdot2\\2x+3y=132\end{cases}\\\\\\
\begin{cases}2x+2y=96\\2x+3y=132\end{cases}\\\\--------(-)\\\\2x-2x+2y-3y=96-132\\\\-y=-36\\\\\boxed{y=36}\\\\\\x+y=48\\\\x+36=48\\\\x=48-36\\\\\boxed{x=12}$

There are 12 rows with exactly 2 passengers and 36 rows with exactly 3 passengers.

3 0

4 years ago