Explanation:
In a magnetic field, the radius of the charged particle is as follows.
r =
where, m = mass, v = velocity
q = charge, B = magnetic field
Therefore, q will be calculated as follows.
q =
=
=
=
= +2e
Thus, we can conclude that the charge of the ionized atom is +2e.
Answer : The correct option is, (D) 3600 kJ
Explanation :
Mass of octane = 75 g
Molar mass of octane = 114.23 g/mole
Enthalpy of combustion = -5500 kJ/mol
First we have to calculate the moles of octane.
Now we have to calculate the heat released in the reaction.
As, 1 mole of octane released heat = -5500 kJ
So, 0.656 mole of octane released heat = 0.656 × (-5500 kJ)
= -3608 kJ
≈ -3600 kJ
Therefore, the heat released in the reaction is 3600 kJ