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3 years ago

The atomic number of an atom is always equal to the total number of

Chemistry

2 answers:

USPshnik [31]3 years ago

4 0

Answer:

yep C is correct!!

Explanation:

Basile [38]3 years ago

3 0

C is correct. Have a good day!

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Consider the reaction between reactants s and o2: 2s(s)+3o2(g)→2so3(g)if a reaction vessel initially contains 7 mols and 9 mol o

nadya68 [22]

Answer: -

1 mol

Explanation: -

Number of moles of Sulphur S = 7

Number of moles of O2 = 9

The balanced chemical equation for the reaction is

2S (s)+3 O2 (g)→2SO3(g)

From the above reaction we can see that

3 mol of O2 react with 2 mol of S

9 mol of O2 will react with $\frac{2 mol S x 9 mol O2}{3 mol O2}$

= 6 mol of S

Unreacted S = 7 - = 1 mol.

If a reaction vessel initially contains 7 mol S and 9 mol O2

1 mole of s will be in the reaction vessel once the reactants have reacted as much as possible

6 0

4 years ago

An unsaturated solution ________.

Greeley [361]

Answer:

I think the answer is D.

Explanation:

Because if it is unsaturated then it can dissolve more solutes.

8 0

3 years ago

_is the only metal that normally exists on earth as a liquid

Aloiza [94]

Answer:

Mercury

Explanation:

mercury, and it's the only metal that normally exists on Earth as a liquid.

8 0

3 years ago

Please help me with this Beer Lambert Law Explanation

tino4ka555 [31]

Answer:

The Beer–Lambert law, also known as Beer's law, the Lambert–Beer law, or the Beer–Lambert–Bouguer law relates the attenuation of light to the properties of the material through which the light is travelling.

Explanation:

Please Mark as brainliest

5 0

2 years ago

Soda ash (sodium carbonate) is widely used in the manufacture of glass. Prior to the environmental movement much of it was produ

egoroff_w [7]

Answer:

NaCl is the limiting reactant

18.0g of CaCO3 are in excess

113.4g Na2CO3 are produced

118.7g CaCl2 are produced

Explanation:

To solve this question we need to convert the mass of each reactant to moles in order to find the limitng and excess reactant to find the amount of products that would be produced:

Moles CaCO3:

125g * (1mol / 100.09g) = 1.25 moles

Moles NaCl:

125g * (1mol / 58.44g) = 2.14 moles

For a complete reaction of 2.14 moles of NaCl are required:

2.14 moles NaCl * (1mol CaCO3 / 2 mol NaCl) = 1.07 moles of CaCO3.

As there are 1.25 moles, Calcium carbonate is the excess reactant and NaCl the limiting reactant

The moles of CaCO3 in excess are:

1.25mol - 1.07mol = 0.18mol CaCO3 and the mass is:

0.18mol CaCO3 * (100.09g / mol) = 18.0g of CaCO3 are in excess

The moles of Na2CO3 and CaCl2 produced are:

2.14 moles NaCl * (1mol Na2CO3-1mol CaCl2 / 2 mol NaCl) = 1.07 moles are produced.

The masses are:

1.07 mol Na2CO3 * (105.99g / mol) = 113.4g Na2CO3

1.07 mol CaCl2 * (110.98g / mol) = 118.7g CaCl2

8 0

3 years ago