Question

1.What is the specific heat capacity of granite when 20 kg absorbs 237 000 J of heat energy, causing its temperature to increase by 15 °C? (you are finding c)​

Answer 1

Given :

• Amount = 20 kg
• Heat energy absorbed = 237,000 J
• Temperature change = 15 °C

Formula applied :

$\boxed {Q = mc \triangle T}$

• Q = absorbed heat
• m = mass
• c = specific heat capacity
• ΔT = temperature change

Let's solve for c !

⇒ 237,000 = 20 × c × 15

⇒ c = 237,000 ÷ 300

⇒ $\boxed {c = 790 J kg^{-1} K^{-1}}$

∴ The specific heat capacity of granite is 790 J kg⁻¹ K⁻¹.