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Masteriza [31]
3 years ago
5

Monty has 16 toy cars in 4 equal groups and 24 toy boats in 3 equal groups. how many more toy boats are in each group than toy c

ars
Mathematics
2 answers:
Alenkinab [10]3 years ago
4 0
16 / 4 = 4 cars  and 24 / 3 = 8 boats  there are 8boats in each group and 4 cars in each group the answer is There are 4 more toy boats in each group than toy cars.
Usimov [2.4K]3 years ago
3 0
Well first we divide 16 by 4 because we have to split the cars up equally in 4 groups and the answer we get to that is 4 so there are 4 cars in each group. Now we do the same for the boats we take 24 and divide by 3 and get 8, so there are 8 boats in each group. Now we take the toy boats in one group because there are obviously more of them and subtract the cars that are in one group and get a difference of 4 which is the answer
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Advocard [28]

Answer:

3.6

Step-by-step explanation:

round ur previous answers to the nearest tenth then subtract them.

5 0
3 years ago
I need you to answer with a, b, c, d
solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

\begin{gathered} ax^2+bx+c=0 \\  \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}

For the given function:

f(x)=2x^2-10x-3x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}x=\frac{10\pm\sqrt[]{100+24}}{4}\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\  \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\  \end{gathered}\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\  \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\  \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Then, the zeros of the given quadratic function are:

\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\  \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Answer: Third option

8 0
1 year ago
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postnew [5]
You FOIL the binomials out to get a quadratic.
7 0
3 years ago
Read 2 more answers
Three girls cut out decimal models of hundredths. Amber doesn't shade any of her models. Grace qualifies three fifths of a model
Varvara68 [4.7K]

Answer:

Amber = 0

Grace = 0.60

Marsha =1.70

Step-by-step explanation:

Given

<em>Decimal Grid = Hundredths</em>

Amber = None

Grace = \frac{3}{5}th

Marsha = 1 + \frac{7}{10}th

To solve for each:

We have:

For Amber:

Amber = 0 * 100

Amber = 0

For Grace:

Grace = \frac{3}{5}th

Grace = \frac{3}{5} * 100

Grace = \frac{300}{5}

Grace = 60

This means that Grace shaded 60 of the hundredth models.

Decimal shaded is:

Grace = 60 * \frac{1}{100}

Grace =\frac{60}{100}

Grace = 0.60

For Marsha:

Marsha = 1 + \frac{7}{10}th

Marsha = \frac{10 + 7}{10}th

Marsha = \frac{17}{10}th

Marsha = 1.7th

Multiply this by 100, to get the number of shaded

Marsha = 1.7 * 100

Marsha = 170

This means that Marsha shaded 170 of the hundredth models.

Decimal shaded is:

Marsha = \frac{170}{100}

Marsha =1.70

5 0
3 years ago
Solve the linear equation by using the Gauss-Jordan elimination method
Paha777 [63]

Answer:  ( x , − x/ 3 − 5 /3 )

Step-by-step explanation:


7 0
3 years ago
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