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Amanda [17]
3 years ago
11

The height in feet of a rocket launched into the air is modeled by the function (t)=-16t^2+160t+300 where t is time in seconds.

Approximately how many seconds will the rocket exceed the height of 500 ft?
Mathematics
1 answer:
liq [111]3 years ago
7 0

approximately 1.5 seconds

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QUESTION
miss Akunina [59]

Answer:

\frac{1}{3600}

Step-by-step explanation:

400^2 = 160,000

5 2/6 = 32/6 = 16/3

6 70/30 = 250/30 = 25/3

16/3 * 25/3 = 400/9

400/9 / 160,000 = 1/3600

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Explain your answer plez
tiny-mole [99]

Answer:

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In a parallelogram, opposing angles must be equal.  Note how 75° = 75°.  Thus, opposing angles 2x + 5 and x + 55 must also be equal.

Solve this equation for x.

Subtracting x from both sides yields x + 5 = 55.  Next:  Subtracting 5 from both sides yields x = 50° (answer choice C)

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mylen [45]
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How many sixths are in 1.5?
mafiozo [28]

Answer:

[three sixths] are the same amount as [one half]

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