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Amanda [17]
3 years ago
11

The height in feet of a rocket launched into the air is modeled by the function (t)=-16t^2+160t+300 where t is time in seconds.

Approximately how many seconds will the rocket exceed the height of 500 ft?
Mathematics
1 answer:
liq [111]3 years ago
7 0

approximately 1.5 seconds

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Information about a play took up 1/3 of the pages in the program. Information about the actors took up 1/4 of the remaining page
Lisa [10]

Answer:

Step-by-step explanation:

Comment

Let the number of pages = x

Play =    1/3x

Actors = 1/4(x - 1/3 x)

Actors = 1/4(2/3x)

Actors = 2/12 x

Producer Director etc = 2 pages

Equation

Actors = 2 pages

2/12 x = 2

Solution

2x/12 = 2               Multiply both sides by 12

12*2x/12 = 2*12     Combine

2x = 24                  Divide by 2

2x/2 = 24/2           Combine

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2 years ago
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krek1111 [17]

Answer:

86 cm²

Step-by-step explanation:

<u>1) Calculate the area of the square</u>

A=lw\\A=20*20\\A=400

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<u>2) Calculate the area of the circle</u>

A=\pi r^2\\

\pi we can substitute with 3.14. To find the radius, we divide the diameter of the circle by 2. 20 cm is the diameter of the circle, so therefore, its radius is 10 cm.

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<u>3) Subtract the area of the circle from the area of the square</u>

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Therefore, the area of the shaded region is 86 cm².

I hope this helps!

3 0
3 years ago
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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Simplify: 2(8 - 2x4).
pentagon [3]

Answer:

<em>2(8-8x)</em>

Step-by-step explanation:

Distrubutive Property:

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A(B+C)=AB+AC

<em>Multiply by the numbers from left to right.</em>

4*2=8

<em>Therefore the correct answer is </em><em>2(8-8x).</em>

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