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maw [93]
3 years ago
13

Which month has the colder average temperatures?

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0
I think january or december

amid [387]3 years ago
7 0
The month has the colder average temperature is that December
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Find the area of the sector.<br> 1350<br> 18 km
harina [27]

Answer:

21870 km^2

Step-by-step explanation:

Area of sector=1/2r^2(theta)

Where r=18 km and theta=135

Area of sector=1/2(18)^2(135)

=1/2(324)(135)

=1/2(43740)

=21870 km^2

7 0
3 years ago
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Add the fractions and simplify the answer 1/2+2/3
koban [17]
The anawer to your question is 3/6, and simplified as 1/2.
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3 years ago
A) Serena walks 4 km in 1 h.<br><br> Explain!
Shkiper50 [21]

Answer:

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6 0
2 years ago
A cube-shaped box has a volume of 1/8 of a cubic meter. What is the perimeter of each of its
belka [17]

Given:

The volume of a cube-shaped box is \dfrac{1}{8} cubic meter.

To find:

The perimeter of each of its faces.

Solution:

Let "a" be the side length of the cube shaped box. Then the volume of the box is:

V=(side)^3

V=a^3

It is given that the volume of a cube-shaped box is \dfrac{1}{8}  cubic meter.

a^3=\dfrac{1}{8}

Taking cube root on both sides, we get

a=\dfrac{1}{2}

Now, the perimeter of each face of a cube is:

P=4a

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P=4\times \dfrac{1}{2}

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5 0
3 years ago
Solve for v -17= 3v - 2 simplify your answer as much as possible
Alika [10]

Answer:

v = -7.5

Step-by-step explanation:

Step 1: Subtract 3v from both sides.

v-17 − 3v = 3v−2 −3v

−2v−17=−2

Step 2: Add 17 to both sides.

−2v−17+17=−2+17

−2v=15

Step 3: Divide both sides by -2.

-2v/2 = 15/2

v = -15/2

v = -7.5

Hope this helps!

Plz name brainliest if possible!

7 0
3 years ago
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