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3 years ago

-3(4x + 9) = 15( Multi-step Equations)please help:)<3

Mathematics

2 answers:

Andrej [43]3 years ago

5 0

Answer:

Step-by-step explanation:

-3(4x + 9) = 15

-12x-27=15

-12x=42

x= -7/2

zimovet [89]3 years ago

4 0

Answer:

x = -7/2

Step-by-step explanation:

-3(4x + 9) = 15

Divide 3 on both sides

-3(4x + 9) /3 = 15 /3

Which makes

4x+9=-5

Subtract 9 on both sides

4x+9 -9 = -5 -9

Which makes

4x=-14

So we divide 4

4x /4 = -14 /4

And we get......

x = -7/2

I hope it's right!

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3 years ago

Find the area of a sector with a central angle of 120° and a diameter of 7.3 cm. Round to the nearest tenth.

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

3 0

3 years ago

Find the value of X, rounded to the nearest tenth. <br> A. 31.8<br> B. 31.4<br> C. 10.3<br> D. 10.7

Molodets [167]

Answer:

31.4

Step-by-step explanation:

x=18/sin35

x= 31.38

=31.4(nearest tenth )

4 0

2 years ago

-3(4x + 9) = 15( Multi-step Equations)please help:)<3​

-3(4x + 9) = 15( Multi-step Equations)please help:)<3