This isn’t an answer but we gotta see the question to answer it ☠️☠️
Answer:
Part a) The slant height is 
Part b) The lateral area is equal to 
Step-by-step explanation:
we know that
The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces
so
![LA=6[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
where
b is the length side of the hexagon
l is the slant height of the pyramid
Part a) Find the slant height l
Applying the Pythagoras Theorem

where
h is the height of the pyramid
a is the apothem
we have


substitute



Part b) Find the lateral area
![LA=6[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
we have


substitute the values
![LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%286%29%283%5Csqrt%7B2%7D%29%5D%3D54%5Csqrt%7B2%7D%5C%20units%5E%7B2%7D)
Answer:
x=4 and y=11
Step-by-step explanation:
x+y=15
5x-y=9
x+5x-y+y=15+9
6x=24
X=4
x+y=15
4+y=15
y=11
Because it equals to 1 either way. To divide 5/6 by 5/6 you turn a fraction upside down and multiply together. 5/6÷5/6→ 5/6×6/5= 1